Mass of vaporized triethylamine : 2.606 g
<h3>Further explanation</h3>
Given
0.5 L triethylamine
P = 18.5 psi
T = 25 °C
Required
mass of vaporized triethylamine
Solution
Conversion :
P 18.5 psi = 1,26 atm
T = 25 +273 = 298 K
Ideal gas law :
PV=nRT
n = PV/RT
Input the value :
n = (1.26 atm x 0.5 L) /(0.08205 x 298)
n = 0.0258
MW triethylamine = 101 g/mol
Mass triethylamine :
= n x MW
= 0.0258 x 101 g/mol
= 2.606 g
Answer is: <span>D. 327,992.8 J.
</span>m(granite) = 17 kg = 17000g.
ΔT(granite) = 21°C - 45°C = -24°C (-24K).<span>
cp(granite</span>)
= 0,804 J/g·°C, <span>specific heat capacity of
granite.
Q = m(granite</span>) · ΔT(granite) · cp(granite).<span>
Q = 17000 g ·(-24</span>°C)<span>· 0,804 J/g·K.
Q = -327990 J.
</span>The granite lost 327990 joules of energy.<span>
Q - </span>amount of energy gained or lost.<span>
</span>
The smaller number is the number of protons, and the greater number is the mass.
C hydroyen
its aht plants breath
