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notsponge [240]
3 years ago
8

Explain why a fluorescent light bulb is not as hot as an incandescent light bulb.

Chemistry
2 answers:
brilliants [131]3 years ago
7 0

When you flick on a light with a regular incandescent bulb, electricity is converted to heat in the tiny, tungsten wire inside. In a 75-watt bulb, the wire heats up to about 4600 degrees Fahrenheit! At such a high temperature, the energy radiating from the wire includes some visible light. Incandescent light bulbs aren’t the most efficient light source, though, because 90% of the electricity they use produces heat, while a measly 10% produces light.

Fluorescent bulbs are designed to produce light without so much heat. Forty percent of the electricity they use produces light, which might not sound so impressive unless you compare it with incandescents.

When you turn on a fluorescent light, electrons collide with mercury atoms inside the bulb, producing ultraviolet light. We can’t see ultraviolet light, so there’s a thin layer of phosphor powder inside the bulb to convert the ultraviolet to visible light. Fluorescent bulbs stay cooler because this process produces much less heat to begin with, and because their bigger size helps disperse heat more quickly.

What do these heated differences mean for energy efficiency? A regular incandescent light bulb uses about four times as much energy as a fluorescent bulb, to produce the same amount of light.
Elina [12.6K]3 years ago
7 0

Particles in plasmas collide more often, but that does not necessarily give them higher temperature.

Plasma particles have high kinetic energy (they move quickly).

Plasma particles are far apart.

The plasma in a fluorescent bulb has a low density.

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0.3824 moles of Zinc
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3 years ago
A compound has a molar mass of 90. grams per mole and the empirical formula CH2O. What is the molecular formula of this compound
Elanso [62]
The molecular formula of this compound is C3H603 XD
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Calculate the mass of 6 moles of H2O
RUDIKE [14]
<span>6mole of H2O contains 18×6 g=108 g</span>
8 0
3 years ago
Read 2 more answers
"46.7 g of water at 80.6 oC is added to a calorimeter that contains 45.33 g of water at 40.6 oC. If the final temperature of the
soldier1979 [14.2K]

<u>Answer:</u> The specific heat of calorimeter is 30.68 J/g°C

<u>Explanation:</u>

When hot water is added to the calorimeter, the amount of heat released by the hot water will be equal to the amount of heat absorbed by cold water and calorimeter.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[(m_2\times c_2)+c_3](T_{final}-T_2)       ......(1)

where,

q = heat absorbed or released

m_1 = mass of hot water = 46.7 g

m_2 = mass of cold water = 45.33 g

T_{final} = final temperature = 59.4°C

T_1 = initial temperature of hot water = 80.6°C

T_2 = initial temperature of cold water = 40.6°C

c_1 = specific heat of hot water = 4.184 J/g°C

c_2 = specific heat of cold water = 4.184 J/g°C

c_3 = specific heat of calorimeter = ? J/g°C

Putting values in equation 1, we get:

46.7\times 4.184\times (59.4-80.6)=-[(45.33\times 4.184)+c_3](59.4-40.6)

c_3=30.68J/g^oC

Hence, the specific heat of calorimeter is 30.68 J/g°C

6 0
3 years ago
Calculate the number of atoms in 2.5 moles of Si.
Ede4ka [16]

Answer:

\boxed {\boxed {\sf About \ 1.5 * 10^{24} \ atoms \ Si}}

Explanation:

When converting from moles to atoms, we must use Avogadro's number. This number tells us there are 6.022 * 10²³ atoms in 1 mole. We can multiply this number by the number of moles.

First, we must set up Avogadro's number as a ratio.

\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}

Next, multiply the number of moles by the ratio.

2.5 \ mol \ Si *\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}

When we multiply, the moles of silicon will cancel.

2.5 * \frac {6.022 \ * 10^{23} \ atoms \ Si }{1}}

Since the denominator of the fraction is 1, we can cancel it out too.

2.5 *  {6.022 \ * 10^{23} \ atoms \ Si }

1.5055 * 10^{24} \ atoms \ Si

The original measurement (2.5 moles) has 2 significant figures (2 and 5). Therefore we must round to 2 sig figs. For this question, 2 sig figs is the tenth place.

The 0 in the hundredth place tells us to leave the 5 in the tenth place.

1.5 * 10^{24} \ atoms \ Si

There are about <u>1.5 * 10²⁴ atoms of silicon.</u>

7 0
2 years ago
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