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notsponge [240]
3 years ago
8

Explain why a fluorescent light bulb is not as hot as an incandescent light bulb.

Chemistry
2 answers:
brilliants [131]3 years ago
7 0

When you flick on a light with a regular incandescent bulb, electricity is converted to heat in the tiny, tungsten wire inside. In a 75-watt bulb, the wire heats up to about 4600 degrees Fahrenheit! At such a high temperature, the energy radiating from the wire includes some visible light. Incandescent light bulbs aren’t the most efficient light source, though, because 90% of the electricity they use produces heat, while a measly 10% produces light.

Fluorescent bulbs are designed to produce light without so much heat. Forty percent of the electricity they use produces light, which might not sound so impressive unless you compare it with incandescents.

When you turn on a fluorescent light, electrons collide with mercury atoms inside the bulb, producing ultraviolet light. We can’t see ultraviolet light, so there’s a thin layer of phosphor powder inside the bulb to convert the ultraviolet to visible light. Fluorescent bulbs stay cooler because this process produces much less heat to begin with, and because their bigger size helps disperse heat more quickly.

What do these heated differences mean for energy efficiency? A regular incandescent light bulb uses about four times as much energy as a fluorescent bulb, to produce the same amount of light.
Elina [12.6K]3 years ago
7 0

Particles in plasmas collide more often, but that does not necessarily give them higher temperature.

Plasma particles have high kinetic energy (they move quickly).

Plasma particles are far apart.

The plasma in a fluorescent bulb has a low density.

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ella [17]

Answer:

Bonjour! Je me demandais si vous pouviez s’il vous plaît traduire vos questions en anglais afin que je puisse les résoudre. J’utilise un traducteur en ce moment pour vous dire votre réponse dans Français. Je suis désolé si vous ne pouvez pas traduire cela. Bonne journée!

Explanation:

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3 years ago
Based on the following thermodynamic data, calculate the boiling point of ethanol in degrees Celsius. Substance ΔH∘f (kJ/mol) S∘
levacccp [35]

Answer:

76.03 °C.

Explanation:

Equation:

C2H5OH(l) --> C2H5OH(g)

ΔHvaporization = ΔH(products) - ΔH (reactants)

= (-235.1 kJ/mol) - (-277.7 kK/mol)

= 42.6 kJ/mol.

ΔSvaporization = ΔS(products) - ΔS(reactants)

= 282.6 J/K.mol - 160.6 J/K.mol

= 122 J/K.mol

= 0.122 kJ/K.mol

Using gibbs free energy equation,

ΔG = ΔH - TΔS

ΔG = 0,

T = ΔH/ΔS

T = 42.6/0.122

= 349.18 K.

Coverting Kelvin to °C,

= 349.18 - 273.15

= 76.03 °C.

8 0
2 years ago
What was one main point of Dalton’s atomic theory
s344n2d4d5 [400]

Answer:

Everything is composed of atoms! which are the indivisible building blocks of matter and cannot be destroyed. All atoms of an element are identical. The atoms of different elements vary in size and mass.

Explanation:

Hope this helped

8 0
2 years ago
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What do coefficients in chemical equations tell you?
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3 years ago
Draw the simplified curved arrow mechanism for the reaction of butan-2-one and CH3Li to give the major product.
Yuki888 [10]

Answer:

Follows are the solution to this question:

Explanation:

Please find the image file of the chemical reaction in the attachment:

In a water medium, the CH3- type CH 3Li is a heavy nucleophile that attacks the carbonyl carbon atom to form the alkoxide ion, which will then be protonated to form alcohol.

8 0
2 years ago
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