The correct answer is making observations in his experiment.
In his cathode ray tube experiment J. J. Thomson proved that the cathode rays are indeed negatively charged particles. He then went on to calculate charge-to-mass ratio of the electron. J. J. Thomson’s pioneering work lest to the theory that the atomic structure is made up of charged particles.
Answer:
Mass = 11.16 g
Explanation:
Given data:
Mass of hydrogen = 8 g
Mass of oxygen = 10 g
Mass of water produced = ?
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen:
Number of moles = mass / molar mass
Number of moles = 8 g/ 2 g/mol
Number of moles = 4 mol
Number of moles of oxygen:
Number of moles = mass / molar mass
Number of moles = 10 g/ 32 g/mol
Number of moles = 0.31 mol
now we will compare the moles of hydrogen and oxygen with water.
O₂ : H₂O
1 : 2
0.31 : 2/1×0.31 = 0.62
H₂ : H₂O
2 : 2
4 : 4
Number of moles of water formed by oxygen are less this it will act as limiting reactant.
Mass of water:
Mass = number of moles × molar mass
Mass = 0.62 mol × 18 g/mol
Mass = 11.16 g
Answer:
pH = 4
Explanation:
pH is a base 10 logarithmic scale
1000 = 10^3
7 -3 = pH = 4
Answer:
• long time lag between planning and operation.
• cost.
• weapons proliferation risk.
• meltdown risk.
• mining lung cancer risk.
• carbon-equivalent emissions and air pollution.
• waste risk.
Explanation:
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