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3 years ago

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How many moles of calcium hydroxide, ca(oh)2, are needed to neutralize 2 moles of sulfuric acid, h2so4?

1 answer:

Ronch [10]3 years ago

3 0

The balanced equation for the neutralisation reaction is as follows
Ca(OH)₂ + H₂SO₄ ---> CaSO₄ + 2H₂O
stoichiometry of Ca(OH)₂ to H₂SO₄ is 1:1
equivalent number of acid reacts with base
number of H₂SO₄ mol reacting - 2 mol
according to molar ratio of 1:1
number of Ca(OH)₂ mol = number of H₂SO₄ moles
therefore number of Ca(OH)₂ moles required - 2 mol

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anzhelika [568]

Answer:

6%

Explanation:

Hello, for this case, we assume that the volume of the solution is 1L, thus, the mass is given by using the density as follows:

$m_{solution}=1L*\frac{1000 mL}{1L}*\frac{0.988g}{1mL} =988g$

Now, the mass of the ethanol:

$m_{C_2H_5OH}=(1.29molC_2H_5OH/L*1L)*\frac{46gC_2H_5OH}{1molC_2H_5OH} \\m_{C_2H_5OH}=59.34g$

Finally, the by mass percent is:

$m/m=\frac{59.34g}{988g}*100\\$ %

%m=6%

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