How many moles of calcium hydroxide, ca(oh)2, are needed to neutralize 2 moles of sulfuric acid, h2so4?

1 answer:

3 0

The balanced equation for the neutralisation reaction is as follows
Ca(OH)₂ + H₂SO₄ ---> CaSO₄ + 2H₂O
stoichiometry of Ca(OH)₂ to H₂SO₄ is 1:1
equivalent number of acid reacts with base
number of H₂SO₄ mol reacting - 2 mol
according to molar ratio of 1:1
number of Ca(OH)₂ mol = number of H₂SO₄ moles
therefore number of Ca(OH)₂ moles required - 2 mol

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$$Molarity=\frac{Weight}{Molecular \,weight} \frac{1000}{V(in \, ml)}$

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