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MArishka [77]
3 years ago
5

How many moles of calcium hydroxide, ca(oh)2, are needed to neutralize 2 moles of sulfuric acid, h2so4?

Chemistry
1 answer:
Ronch [10]3 years ago
3 0
The balanced equation for the neutralisation reaction is as follows 
Ca(OH)₂ + H₂SO₄ ---> CaSO₄ + 2H₂O
stoichiometry of Ca(OH)₂ to H₂SO₄ is 1:1
equivalent number of acid reacts with base
number of H₂SO₄ mol reacting - 2 mol
according to molar ratio of 1:1
number of Ca(OH)₂ mol = number of H₂SO₄ moles 
therefore number of Ca(OH)₂ moles required - 2 mol
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For elements 1–36, there are two exceptions to the filling order as predicted from the periodic table. draw the atomic orbital d
boyakko [2]

Here we have to draw the atomic orbital diagram of the elements present in the range of ¹H to ³⁶Kr having exception and its number of unpaired electrons present in the molecule.

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²⁴Cr = 1s²2s²2p⁶3s²3p⁶3d⁵4s¹.

²⁹Cu = 1s²2s²2p⁶3s²3p⁶3d¹⁰4s¹.

The number of unpaired electrons in Cr and Cu are 6 and 1 respectively.

The atomic orbital diagram of the elements in periodic table is governed by the three rules or principles. Those are (i) The Aufbau principle, (ii) The Pauli exclusion principle and (iii) Hund''s rule of maximum multiplicity.

Among it the Aufbau principle explain the energy level of the atomic orbitals 1s < 2s 2p < 3s < 3P < 3d < 4s etc.

The Pauli's principle tells number of maximum electrons can be present in a particular orbital. As per the principle the s, p and d orbital can posses  maximum 2, 6 and 10 electrons.

the Hund's rules explains the extra stability of the half filled and full filled orbitals.

In ²⁴Cr (after ²³V: 1s²2s²2p⁶3s²3p⁶3d³4s²) the expected electronic configuration is 1s²2s²2p⁶3s²3p⁶3d⁴4s² having four unpaired electron but as the half filled d-orbital (5 electrons) is more stable thus it posses 1s²2s²2p⁶3s²3p⁶3d⁵4s¹ electronic configuration having 6 unpaired electrons.

In ²⁹Cu (after ²⁸Ni: 1s²2s²2p⁶3s²3p⁶3d⁸4s²) the expected electronic configuration is 1s²2s²2p⁶3s²3p⁶3d⁹4s² having 1 unpaired electron in d orbital, but due to high stability of the fulfilled d orbital (10 electrons) the atomic orbital diagram become 1s²2s²2p⁶3s²3p⁶3d¹⁰4s¹ having same number of unpaired electron is s orbital.

The two exceptional atomic orbital diagram of the element in between ¹H to ³⁶Kr is drawn and number of unpaired electrons are calculated.              

6 0
3 years ago
What is the number of moles in 40.0 L of He gas at STP?
Alla [95]

Answer: There are 1.78 moles in 40.0 L of He gas at STP

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (STP)

V = Volume of gas = 40.0  L

n = number of moles = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =273K   (STP)

n=\frac{PV}{RT}

n=\frac{1atm\times 40.0L}{0.0821Latm/K mol\times 273K}=1.78moles

Thus there are 1.78 moles in 40.0 L of He gas at STP

8 0
3 years ago
Now that you have the knowledge of the highest specific heat capacity and lowest porosity, which material would you choose to bu
Svet_ta [14]

Answer:

Now that you have the knowledge of the highest specific heat capacity and lowest porosity, which material would you choose to build Rover's new doghouse roof?

Oak has the highest heat capacity; therefore, oak can absorb a lot of heat without raising its temperature. This is good for very hot areas. Concrete has the lowest porosity so water will not leak through its pores and drip into the doghouse. This is good for rainy areas. However, clay is second on both lists and might be a good choice overall for hot and rainy weather conditions. Rover should be happy with this.

xXxAnimexXx

Have a great day!

7 0
3 years ago
Read 2 more answers
Determine the mass of NaOH needed to make 750.0mL of a 6.00 M solution of NaOH
fredd [130]

Answer: 180g

Explanation:

No of moles= volume ×molarity/1000

Volume is given as 750ml

Molarity is given as 6M

Substitute to get the mole

No of moles = 750×6/1000

No of moles= 4.5moles

Remember that

No of moles also = mass given/molar mass

Molar mass of NaOH

Na= 23

O=16

H=1

Molar mass = na +o+h

Molar mass =23+16+1

Molar mass=40g/mol

Substitute

No of moles = mass given/molar mass

Mass = 4.5×40

Mass = 180g

The mass of NaOH needed is 180g

3 0
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