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Contact [7]
2 years ago
14

A standard deck of playing cards has 13 cards in each of four suits: hearts, clubs, diamonds, and spades. Two cards are chosen f

rom the deck at random. What is the probability of choosing one club and one spade?
Mathematics
1 answer:
Aloiza [94]2 years ago
5 0

Answer:

Probability of choosing one club and one spade = 0.6025

Step-by-step explanation:

Total number of cards= 52 cards

For the first event

Probability of choosing a club

Toatal club = 13 cards

Probability of choosing a club

= 13/52

Probability of choosing a club

= 1/4

Probability of choosing a club

=0.25

For the second event

Probability of choosing a spade

Toatal spade = 13 cards

Probability of choosing a spade

= 13/52

Probability of choosing spadep

= 1/4

Probability of choosing a spade = 0.25

Probability of both = 0.25*0.25

Probability of both = 0.6025

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Step-by-step explanation:

3×3=9+2=11. so 3 is the answer.

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3 years ago
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Solve for x: −2(x + 3) = −4(x + 1) − 4
Stolb23 [73]

Hello! My name is Chris and I’ll be helping you with this problem.

Date: 9/27/20  Time:  

Answer:  

x = -1

Explanation:

Step 1: Simplify both sides of the equation.

−2(x+3)=−4(x+1)−4

(−2)(x)+(−2)(3)=(−4)(x)+(−4)(1)+−4(Distribute)

−2x+−6=−4x+−4+−4

−2x−6=(−4x)+(−4+−4)(Combine Like Terms)

−2x−6=−4x+−8

−2x−6=−4x−8

Step 2: Add 4x to both sides.

−2x−6+4x=−4x−8+4x

2x−6=−8

Step 3: Add 6 to both sides.

2x−6+6=−8+6

2x=−2

Step 4: Divide both sides by 2.

2x  = -2

/2      /2

x=−1

I hope this helped answer your question! Have a great rest of your day!

Furthermore,  

Chris

5 0
3 years ago
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