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Zielflug [23.3K]
3 years ago
7

State the order of the given ordinary differential equation.

Mathematics
1 answer:
sdas [7]3 years ago
6 0
2nd Order because it contains a 2nd derivative ,y''

Linear because the y term is linear, in other words the y has no exponent, nor is it inside of a log or trig function.
ex:
ln(y) or sin(y) or e^y
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Can someone please explain how to do number 23 I have no idea how to do it.
taurus [48]
Ok so first equate all the three equations whether by substituting or by eliminating then choose the one das not the answer
3 0
2 years ago
Let m = 7.
Zolol [24]
32 is the answer to the problem


4 0
2 years ago
Read 2 more answers
(1/3)^x^1/4 • (1/3)^x^2/3
monitta
Wait i’m confused on how this equation is modeled i’m sorry do you have a picture? i wanna be sure i answer this right.
5 0
3 years ago
The Pythagorean Theorem- Find the Missing Length:
drek231 [11]

The miles he drove North on Avenue B is 24 miles.

<h3>What is Pythagoras theorem? </h3>

According to the Pythagoras theorem, the square of the hypotenuse is the sum of the square of the opposite sides.

The Pythagoras theorem: a² + b² = c²

Where:

  • a = length
  • b = base = 7 miles
  • c = hypotenuse = 25 miles

<h3>How many miles did he drive north of Avenue B? </h3>

25² - 7²

625 - 49 = 576

√576 = 24 miles

Please find attached the required diagram. To learn more about Pythagoras theorem, please check: brainly.com/question/14580675

5 0
2 years ago
A right triangle has legs measuring 4.5 meters and 1.5 meters. The lenghts of the legs of a second triangle are proportional to
Eduardwww [97]
We know that
in the first triangle
the ratio of the legs are
4.5/1.5-----> 3

then
case <span>A) 6 m and 2 m ------> ratio=6/3----> 3
so
</span><span>the legs of a second triangle are proportional to the lengths of the legs of the first triangle

</span>case B) 8 m and 5 m ------> ratio=8/5---->1.6
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle

case C) 7 m and 3.5 mm ------> ratio=7/3.5---->2
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle


case D) 10 m and 2.5 m ------> ratio=10/2.5---->4
so
the legs of a second triangle are not proportional to the lengths of the legs of the first triangle

case E) 11.25 m and 3.75 m ------> ratio=11.25/3.75---->3
so
the legs of a second triangle are  proportional to the lengths of the legs of the first triangle

the answer is
A) 6 m and 2 m
E) 11.25 m and 3.75 m




4 0
3 years ago
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