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KengaRu [80]
3 years ago
13

The length of one leg of a right triangle is 24ft and the length of the hypotenuse is 40ft what is the length of the other leg

Mathematics
2 answers:
lukranit [14]3 years ago
8 0
Use formula a squared equals to c squared minus b squared

40^2-24^2 is 1024

Square root of 1024 is 32.0
Sedbober [7]3 years ago
3 0
24^2+b^2=40^2
B is the unknown leg so we have to figure that out by plugging in what we know into the format a^2+b^2=c^2
Which is 24^2+b^2=40^2
So 24^2=576
And leave the b^2
Then 40^2=1600
Your new equation is 576+b^2=1600
Subtract 576 from both sides so you get b^2=1,024 to find b you find the square root of 1,024 to get b by itself which now gives you b=32 this means that the length of the other leg is 32.0. Hope this helps! :)
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scoundrel [369]

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6 0
3 years ago
Select an expression equal to 6(4q + 8r)​
Masteriza [31]

Answer: B: 24q+48r

Step-by-step explanation: 6(4q+8r)

=(6)(4q+8r)

=(6)(4q)+(6)(8r)

=24q+48r

 

8 0
3 years ago
Please prove this........​
Crazy boy [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
3 years ago
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malfutka [58]

Answer:

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The given parameters are;

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The amount the broker received per share, E = $0.30

Therefore, the amount of profit, 'P', is given as follows;

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6 0
3 years ago
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m_a_m_a [10]

Answer:

Step-by-step explanation:

Area is half base × height

If area = 140 and height = 20 inches

base =140 ÷ 20 = 7 × 2 = 14 inches

3 0
4 years ago
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