Question

Mary gave her brother 1/4 of her plums and her sister 1/3 of her plums.Mary remained with 20 plums.Caluculate how many plums mary had before sharing and how many more plums her sister received than her brother

Answer 1

Answer:

Step-by-step explanation:

Let x be the number plums that Mary had

Number of plums received by her brother = (1/4) of x  =(1/4)x

Number of plums received by her sister = (1/3)x

Remaining plums is 20.

Total plums - (plums given to brother + plums given to sister) = 20

$x-(\frac{1}{4}x+\frac{1}{3}x)=20\\\\x-\frac{1}{4}x-\frac{1}{3}x=20\\\\\frac{1*12}{1*12}x-\frac{1*3}{4*3}x-\frac{1*4}{3*4}x=20\\\\\frac{12}{12}x-\frac{3}{12}x-\frac{4}{12}x=20\\\\\frac{12-3-4}{12}x=20\\\\\frac{5}{12}x=20\\\\x=20*\frac{12}{5}\\\\x=4*12\\\\x=48$

Number of plums with Mary = 48

Number of plums received by brother= (1/4)*48 = 12 plums

Number of plums received by sister = (1/3)*48 = 16 plums

16 - 12 = 4

Her sister received 4 plums more than her brother