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fomenos
3 years ago
6

A 6.5 kg rock thrown down from a 120m high cliff with initial velocity 18 m/s down. Calculate

Physics
1 answer:
ra1l [238]3 years ago
6 0

Answer:

this is the answer......

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a 15kg television sits on a shelf at a height of 0.3 m how much gravitational potential energy is added to the television when i
DedPeter [7]

Answer:

<h2>103 Joules</h2>

Explanation:

In this problem we are required to find the potential energy possessed by the television

Given data

mass of television m = 15 kg

height  added above the ground, h= 1-0.3 = 0.7 m

acceleration due to gravity g = 9.81 m/s^2

apply the formula for potential energy we have

P.E= m*g*h

P.E = 15*9.81*0.7 = 103 Joules

7 0
3 years ago
Why is the meteor shower is best observed after midnight?​
harkovskaia [24]

Answer:

At dawn your location on earth is pointed straight in the direction of the Earth's travel in its orbit.  Between midnight and dawn you are moving head-on through the location of the meteors in space, which means that you will, on average, observe more of them.

- public.nrao.edu

Explanation:

hope this helps

4 0
3 years ago
A 3.90 kg block is in equilibrium on an incline of 31.0◦. The acceleration of gravity is 9.81 m/s2 . What is Fn of the incline o
storchak [24]

Answer:

Explanation:

The sum of the pore along the plane is expressed according to Newton's law

Fn-Ff = ma

Fn is the moving force

Ff = nR = frictional force

m is the Mass

a is the acceleration

Substitute the given values

Fn - nR = ma

Fn - tan31°(mgcostheta) =3.9(9.8)

Fn - tan31(3.9(9.8)cos31) = 3.9(9.8)

Fn - tan31(38.22cos31)= 38.22

Fn - 32.76tan31 = 38.22

Fn-19.68 = 38.22

Fn = 38.22+19.68.

Fn = 57.90N

Hence Fn (moving force) of the inclined block is 57.90

4 0
3 years ago
Atoms in a solid are not stationary, but vibrate about their equilibrium positions. Typically, the frequency of vibration is abo
hoa [83]

To develop this problem it is necessary to use the equations of description of the simple harmonic movement in which the acceleration and angular velocity are expressed as a function of the Amplitude.

Our values are given as

f = 4.11 *10^{12} Hz

A = 1.23 * 10^{-11}m

The angular velocity of a body can be described as a function of frequency as

\omega = 2\pi f

\omega = 2\pi 4.11 *10^{12}

\omega=2.582*10^{13} rad/s

PART A) The expression for the maximum angular velocity is given by the amplitude so that

V = A\omega

V =( 1.23 * 10^{-11})(2.582*10^{13})

V =  = 317.586m/s

PART B) The maximum acceleration on your part would be given by the expression

a = A \omega^2

a =( 1.23 * 10^{-11})(2.582*10^{13})^2

a= 8.2*10^{15}m/s^2

4 0
3 years ago
You move a 25 N object 5 meters. If it takes 8 s how much power did you do?
klasskru [66]

Answer:

15.625 watts

Explanation:

Recall that power is defined as the worked performed per unit of time:

Power = Work / time

The work done is Force * distance, so in our case the work is:

Work = 25 M * 5 m = 125 J

Then the power will be:

Power = 125 J / 8 sec = 15.625 watts

6 0
2 years ago
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