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4 years ago

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A 6157 N piano is to be pushed up a(n) 2.41 m frictionless plank that makes an angle of 21.9 ◦ with the horizontal. Calculate th

e work done in sliding the piano up the plank at a slow constant rate.

1 answer:

xz_007 [3.2K]4 years ago

3 0

Answer:

Work done, W = 5534.53 J

Explanation:

It is given that,

Force acting on the piano, F = 6157 N

It is pushed up a distance of 2.41 m friction less plank.

Let W is the work done in sliding the piano up the plank at a slow constant rate. It is given by :

$W=Fd\ sin\theta$

Since, $F=F\ sin\theta$ (in vertical direction)

$W=6157\times 2.41\ sin(21.9)$

W = 5534.53 J

So, the work done in sliding the piano up the plank is 5534.53 J. Hence, this is the required solution.

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we substitute

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we substitute in the endowment equilibrium equation

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μ = cotan θ (W / 2 + 0,3 W_painter) / (W + W_painter)

we substitute the values they give

μ = cotan θ (12/2 + 0.3 55) / (12 + 55)

μ = cotan θ (22.5 / 67)

μ = cotan tea (0.336)

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