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3 years ago

7

How much is a ball that is tethered to a post accelerating if its linear speed is 3.5 m/s and the ball is 0.91 meters away from

the pole? a = v^2 / r

1 answer:

FinnZ [79.3K]3 years ago

7 0

Answer:

$a_{c} = 13.46\ m/s^2$

Explanation:

The motion of the tethered ball around the pole can be modeled as uniform circular motion. The acceleration of the objects executing uniform circular motion is due to the change in direction of their velocity. This is called centripetal acceleration. It is given by the following formula:

$a_{c} = \frac{v^2}{r}$

where,

ac = centripetal acceleration = ?

v = speed of ball = 3.5 m/s

r = distance of ball from center of rotation = 0.91 m

Using these values in equation, we get:

$a_{c} = \frac{(3.5\ m/s)^2}{0.91\ m}\\\\a_{c} = 13.46\ m/s^2$

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3 years ago

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Argon in the amount of 1.5 kg fills a 0.04-m3 piston cylinder device at 550 kPa. The piston is now moved by changing the weights

Arlecino [84]

Answer:

275 kPa

Explanation:

mass of the gas=m=1.5 kg

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V₂=final volume

V₂=2 V₁

As the temperature is constant

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$\frac{P1V1}{T1}$ = $\frac{P2 V2}{T2}$

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$\frac{P1V1}{T1}$ = $\frac{P2 *2V1}{T2}$

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4 years ago

A cannon is mounted on a tower above a wide, level field. The barrel of the cannon is 20 m above the ground below. A cannonball

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<u>Answer:</u>

Cannonball will be in flight before it hits the ground for 2.02 seconds

<u>Explanation:</u>

Initial height from ground = 20 meter.

We have equation of motion , $s= ut+\frac{1}{2} at^2$ , s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this the velocity of body in vertical direction = 0 m/s, acceleration = 9.8 $m/s^2$ , we need to calculate time when s = 20 meter.

Substituting

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3 years ago

Jeff, a snowboarder who weighs 1000 N, is practicing on a trampoline for an upcoming competition. As Jeff bounces straight up of

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Answer:

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Explanation:

Given data

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$E_K = \frac{1}{2} m v^{2}$

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3 years ago

A larger object is made of two balls separated by a massless rigid rod that is 1.5 m long. The mass of the red ball at one end i

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Answer:

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Explanation:

Given :

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Hence , this is the required solution .

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