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Sladkaya [172]
3 years ago
8

At the equator, the earth spins a distance of

Physics
1 answer:
valentina_108 [34]3 years ago
3 0

Answer:

About 1080 miles per hour

Explanation:

If the earth spins 25,922 miles everyday (24 hours) then is would spin about 1080 miles per hour.

25 922 miles / 24

24 divided by 24 to get 1 ( 1 hour)

*if we divided 24 by 24 then we do the same to 25 922 (to make it equivalent)

25 922 divided by 24 = 1080.083333333333.

So, 1080 mph or 1080 miles / 1 hour

I hope this helped :)

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How is the magnetic force on a particle moving in a magnetic field different from gravitational and electric forces.
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Answer:

The magnetic force on a free moving charge depends on the velocity of the charge and the magnetic field, direction of the force is given by the right hand rule. While gravitational depends on the mass and distance of the moving particle and electric forces depends on the magnitude of the charge and distance of separation.

Explanation:

The magnetic force on a free moving charge depends on the velocity of the charge and the magnetic field and direction of the force is given by the right hand rule. While gravitational depends on the mass and distance of the moving particle and electric forces depends on the magnitude of the charge and distance of separation.

The magnetic force is given by the charge times the vector product of velocity and magnetic field. While gravitational force is given by the square of the particle mass divided by the square its distance of separation. Also electric forces is given by the square of the charge magnitude divided by the square its distance separation.

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51. Suppose you measure the terminal voltage of a 3.200-V lithium cell having an internal resistance of 5.00Ω by placing a 1.00-
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Explanation:

Given that,

Terminal voltage = 3.200 V

Internal resistance r= 5.00\ \Omega

(a). We need to calculate the current

Using rule of loop

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Where, E = emf

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r = internal resistance

Put the value into the formula

I=\dfrac{3.200}{1.00\times10^{3}+5.00}

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(b). We need to calculate the terminal voltage

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Put the value into the formula

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