Chemical testing of water

What is a gravitational force? give two examples to illustrate it.

fredd [130]

Answer:

The gravitational force is a force that attracts any two objects with mass.

Explanation:

Some examples of the force of gravity include: The force that holds the gases in the sun. The force that causes a ball you throw in the air to come down again.

7 0

4 years ago

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A 6.0-kg object, initially at rest in free space, "explodes" into three segments of equal mass. Two of these segments are observ

sladkih [1.3K]

Answer:

$Q = 2000 J$

Explanation:

As we know that the 6 kg object was at rest initially

So here since net force on the system is zero

so the momentum of the system will always remains conserved

so we can say

$0 = P_1 + P_2 + P_3$

now we know that

$P_1 = P_2 = P$

and the angle between the two objects is 60 degree

so we can say

$\vec P_1 + \vec P_2 = \sqrt{P_1^2 + P_2^2 + 2P_1 P_2cos60}$

$\vec P_1 + \vec P_2 = \sqrt{P^2 + P^2 + 2P^2(0.5)} = \sqrt3 P$

now we can say that the speed of the third mass will be

$v_3 = \sqrt 3 (20) m/s$

now the total kinetic energy released in this system is given as

$Q = \frac{1}{2}mv_1^2 + \frac{1}{2}mv_2^2 + \frac{1}{2}mv_3^2$

$Q = \frac{1}{2}(2)(20^2) + \frac{1}{2}(2)(20^2) + \frac{1}{2}(2)(20\sqrt3)^2$

$Q = 2000 J$

3 0

4 years ago

Two parallel conducting plates are connected to a constant voltage source. The magnitude of the electric field between the plate

Alecsey [184]

Answer:

The magnitude of the new electric field is <u>35820 N/C</u>.

Explanation:

Given:

Original magnitude of electric field (E₀) = 2388 N/C

Original voltage = 'V' (Assume)

Original separation between the plates = 'd' (Assume)

Now, new voltage is three times original voltage. So, $V_n=3V$

New distance is 1/5 the original distance. So, $d_n=\dfrac{d}{5}$

Now, electric field between the parallel plates originally is given as:

$E_0=\frac{V}{d}=2388\ N/C$

Let us find the new electric field based on the above formula.

$E_n=\frac{V_n}{d_n}\\\\E_n=\frac{3V}{\frac{d}{5}}\\\\E_n=15(\frac{V}{d})$

Now, $\frac{V}{d}=2388\ N/C$ . So,

$E_n=15\times 2388=35820\ N/C$

Therefore, the magnitude of the new electric field is 35820 N/C.

3 0

3 years ago

A student standing on a stationary skateboard tosses a textbook with a mass of mb = 1.25 kg to a friend standing in front of him

juin [17]

Answer:

The velocity of the student has after throwing the book is 0.0345 m/s.

Explanation:

Given that,

Mass of book =1.25 kg

Combined mass = 112 kg

Velocity of book = 3.61 m/s

Angle = 31°

We need to calculate the magnitude of the velocity of the student has after throwing the book

Using conservation of momentum along horizontal direction

$m_{b}v_{b}\cos\theta= m_{c}v_{c}$

$v_{s}=\dfrac{m_{b}v_{b}\cos\theta}{m_{c}}$

Put the value into the formula

$v_{c}=\dfrac{1.25\times3.61\times\cos31}{112}$

$v_{c}=0.0345\ m/s$

Hence, The velocity of the student has after throwing the book is 0.0345 m/s.

3 0

3 years ago

Which of these statements best proves that electromagnetic forces are weaker than strong nuclear forces? Neutrons do not repel o

musickatia [10]

Answer: <span>Protons do not move out of the nucleus of atoms although they repel each other.

Reasoning:

Remember that protons are particles with positive charge and they held together in the nucleus of the atom which is a tiny tiny region. As you know, like charges repel each other, which means that the protons exert a repulsion force.

That repulsion force tends to destabilize the atom. The only reason why the atom does not explode is because there is a there exists a force of attraction that exceeds the repulsion of the like charged protons. That is the strong nuclear force. Therefore, the strong nuclear forces are stronger than the electromagnetic force that tends to get the protons apart.
</span>

7 0

3 years ago