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Alexxandr [17]
3 years ago
7

Was the object accelerating during the time interval labeled “B”? A) Yes B) No

Physics
2 answers:
Oxana [17]3 years ago
7 0
Yes it was accelerating
Alla [95]3 years ago
5 0

There's not enough information in the graph to determine whether it was or it wasn't.  It could have been, but we can't tell.

Before I explain this answer, it's VERY important to know exactly what "accelerating" means:

-- "Accelerating" does NOT always mean "speeding up".

-- "Accelerating" means ANY change in velocity.

-- That can be ==> <u>speeding up</u>, or ==> <u>slowing down</u>, or ==> <u>turning</u>.

This graph is labeled "Velocity vs Time", but it isn't really. "Velocity" means <u>speed</u> AND <u>direction</u>. The graph only shows us the object's speed, but nothing about its direction.

During time-interval-B, the speed isn't changing, but the object could still be changing <u>direction</u>, like turning a corner, or on a curved path. We don't know. The graph doesn't show us that information.

The object could be accelerating during time-interval-B. It's true that the speed wasn't changing. But maybe the direction was. If the direction was changing, then we have to say the object was 'accelerating' during the interval labeled B .  

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A wave has a wavelength of 4.9 m and a velocity of 9.8 m/s. The medium through which this wave is traveling is then heated so th
garri49 [273]

Answer:

the wavelength is 9.8 meters

Explanation:

We can use the relationship:

Velocity = wavelenght*frequency.

Initially we have:

wavelenght = 4.9m

velocity = 9.8m/s

then:

9.8m/s =  4.9m*f

f = 9.8m/s/4.9m =  2*1/s

now, if the velocity is doubled and the frequency remains the same, we have:

2*9.8m/s = wavelenght*2*1/s

wavelenght = (2*9.8m/s)*(1/2)s = 9.8 m

6 0
3 years ago
Read 2 more answers
A 1400 kg car is traveling east on the highway at 31 m/s and collides into the rear of a slower moving pickup truck of 2400 kg,
zloy xaker [14]

Answer: 31 m/s due east

Explanation: this question can be solved using the law of conservation of linear momentum.

This law states that in a closed or isolated system, during collision, the vector sum of momentum before collision equals the vector sum of momentum after collision.

Momentum = mass × velocity

From our question, our parameters before collision are given below as

Mass of car = mc = 1400kg

Speed of car =vc = 31 m/s (due east)

Mass of truck = mt = 2400kg

Velocity of truck = vt = 25 m/s ( due east )

After collision

Velocity of car = ?

Velocity of truck = 34 m/s ( due east )

Vector sum of momentum before collision is given as

1400 (31) + 2400 (25) = 43400 + 60000 = 103400 kgm/s

After collision the truck is seen to move faster (v = 34 m/s) which implies that the car also moves due east .

1400 (v) + 2400(25) .... A positive value is between both momenta because they are in the same direction.

After collision, we have that

1400v + 60000

Vector sum of momentum before collision = vector sum of momentum after collision

103400 = 1400v + 60000

103400 - 60000 = 1400v

43400 = 1400v

v = 43400/ 1400

v = 31 m/s due east

4 0
4 years ago
In a two-slit experiment using coherent light, the distance between the slits and the screen is 1.10 m, and the distance between
Paul [167]

Answer:

D) 763 nm

Explanation:

Calculation for the wavelength of light

Using this formula

Wavelength of light=Delta Y*Distance / Length

Where,

Delta Y represent the 2nd order bright fringe

Length represent the distance between both the slits and the screen

Distance represent the Distance between the slits

Let note that cm to m = (4.2) x 10^-2 and mm to m= ( 0.0400x 10^-3)

Now Let plug in the formula

Wavelength of light=[(4.2 x 10^-2m)(0.0400 x 10^-3m) / 2(1.1m)]*10^-7 meters

Wavelength of light=[(0.042m) (0.0004m)/2.2m]*10^-7 meters

Wavelength of light =(0.0000168m/2.2m)*10^-7 meters

Wavelength of light =7.63 *10^-7 meters

Wavelength of light =763 nm

Therefore the Wavelength of light will be 763 nm

3 0
3 years ago
Which one of the following is not a fundamental physical quantity??! A. Temperature b. Current c. Area d. Mass​
Hatshy [7]

Answer:

Out of this, Area is not a fundamental physical quantity.

3 0
3 years ago
Many of the male characteristics come from which reproductive hormone?
motikmotik

Answer:

The answer is C. Testosterone.

Explanation:

Thats what make us a male.

8 0
2 years ago
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