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Ray Of Light [21]
3 years ago
11

Which word is not a good way to describe exercise?

Physics
1 answer:
Karolina [17]3 years ago
3 0
In my opinion, calling exercise "work"  wouldn't be a good way of describing it, I don't think people would exercise if its called work 
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Types of cell combination? in electricity​
Grace [21]

Answer:

Series and Parallel

7 0
3 years ago
Someone please help me for a brainliest but it has to be correct
Katarina [22]
The answer is 34 you have to add the numbers and divide them by how many numbers there are
7 0
3 years ago
Read 2 more answers
How far will a freely falling object fall from rest in six seconds?
navik [9.2K]
Here are two ways to do it:

<u>Way #1:</u>
-- You know that gravity accelerates things that are falling freely, adding 9.8 m/s to their speed every second.

-- After 6 seconds, an object that fell from rest winds up falling at (9.8 x 6) = 58.8m/s.

-- During that time, its average speed was 1/2(0 + 58.8) = 29.4 m/s .

-- In 6 seconds, at an average speed of 29.4 m/s, it covers (29.4 x 6) = <em>176.4meters</em>.

<u>Way #2:</u>
This way only works if you remember the formula for the distance covered during uniform acceleration.

             D  =  1/2 (acceleration) (time)²

Acceleration = gravity = 9.8 m/s²
Time  =  6 seconds

           D  =  1/2 (9.8) (6)²  =  <em>176.4 meters</em>.
4 0
3 years ago
Read 2 more answers
Three polarizing filters are stacked, with the polarizing axis ofthe second and third filters at angles of 22.2^\circ and 68.0^\
andreev551 [17]

Answer:

I₂ = 25.4 W

Explanation:

Polarization problems can be solved with the malus law

     I = I₀ cos² θ

Let's apply this formula to find the intendant intensity (Gone)

Second and third polarizer, at an angle between them is

    θ₂ = 68.0-22.2 = 45.8º

    I = I₂ cos² θ₂

    I₂ = I / cos₂ θ₂

    I₂ = 75.5 / cos² 45.8

    I₂ = 155.3 W

We repeat for First and second polarizer

   I₂ = I₁ cos² θ₁

   I₁ = I₂ / cos² θ₁

   I₁ = 155.3 / cos² 22.2

   I₁ = 181.2 W

Now we analyze the first polarizer with the incident light is not polarized only half of the light for the first polarized

    I₁ = I₀ / 2

   I₀ = 2 I₁

   I₀ = 2 181.2

   I₀ = 362.4 W

Now we remove the second polarizer the intensity that reaches the third polarizer is

    I₁ = 181.2 W

The intensity at the exit is

    I₂ = I₁ cos² θ₂

    I₂ = 181.2 cos² 68.0

   I₂ = 25.4 W

8 0
3 years ago
Why can't passenger planes fly very high?
Archy [21]
<span>It is not that jet engines perform better at higher altitude, but rather they are more fuel efficient. Performance is far greater at lower altitudes. Just think about when you are taking off and the airplane accelerates quickly and pitches way up. There's lots of extra thrust down low to allow that. The fuel/air ratio remains somewhat constant through the climb. As altitude increases, the air thin outs and therefore, so can the fuel flow. Airlines try for the most efficient routes and altitudes as possible to save money. They do however change altitudes in flight (higher or lower) when needed for weather and turbulence avoidance. --- And a note about the jet stream, it is relatively narrow and always curving, so the time an airliner would spend there is very short. And another thing, it flows mostly west to east isn't the U.S. so a westbound flight would be at a disadvantage. Airlines still fly high whether traveling East or West.</span>
4 0
3 years ago
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