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Ray Of Light [21]

3 years ago

11

Which word is not a good way to describe exercise?

1 answer:

Karolina [17]3 years ago

3 0

In my opinion, calling exercise "work" wouldn't be a good way of describing it, I don't think people would exercise if its called work

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If you wanted to increase the gravitational force between two objects what would you do

adelina 88 [10]

Double the force on the object

6 0

3 years ago

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What is a reasonable measurement for the distance to Neptune?

IRINA_888 [86]

Answer:

30 kilometers is a reasonable measurement

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3 years ago

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The resistance of a very fine aluminum wire with a 20 μm × 20 μm square cross section is 1200 Ω . A 1200 Ω resistor is made by w

notsponge [240]

Explanation:

The given data is as follows.

Resistance (R) = 1200 ohm, Area (A) = $20 \times 10^{-6}$ m (as $1 \mu m = 10^{-6} m$ )

Diameter (d) = 2.3 mm = $2.3 \times 10^{-3}$ m

First, we will calculate the length as follows.

R = $\rho \frac{L}{A}$

Here, $\rho$ = resistivity of aluminium = $2.65 \times 10^{-8}$

Putting the given values above and we will calculate the value of length as follows.

R = $\rho \frac{L}{A}$

1200 = $2.65 \times 10^{-8} \times \frac{L}{20 \times 10^{-6}}$

L = $9.056 \times 10^{5}$

As the circumference of circular wire = $2 \pi r$

or, = $2 \times \pi \times \frac{d}{2}$

= $\pi \times d$

And, number of turns will be calculated as follows.

No. of turns × Circumference = Length of wire

No. of turns × $3.14 \times 2.3 \times 10^{-3} = 9.056 \times 10^{5}$

= $1.25 \times 10^{8}$

Thus, we can conclude that $1.25 \times 10^{8}$ turns of wire are needed.

6 0

3 years ago

Which is a chemical property that can be used to identify calcium carbonate?

Anna71 [15]

(D) reacts with acids by producing gas bubbles
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(A) White Color

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An airplane is flying through a thundercloud at a height of 2000 m (This is a very dangerous thing to do because of updrafts, tu

Doss [256]

Answer:

$400000\ \text{N/C}$

Explanation:

$q_1$ = Charge at 3000 m = 40 C

$q_2$ = Charge at 1000 m = -40 C

$r_1$ = 3000 m

$r_2$ = 1000 m

k = Coulomb constant = $9\times10^9\ \text{Nm}^2/\text{C}^2$

Electric field due to the charge at 3000 m

$E_1=\dfrac{k|q_1|}{r_1^2}\\\Rightarrow E_1=\dfrac{9\times 10^9\times 40}{3000^2}\\\Rightarrow E_1=40000\ \text{N/C}$

Electric field due to the charge at 1000 m

$E_2=\dfrac{k|q_2|}{r_2^2}\\\Rightarrow E_2=\dfrac{9\times 10^9\times 40}{1000^2}\\\Rightarrow E_2=360000\ \text{N/C}$

Electric field at the aircraft is $E_1+E_2=40000+360000=400000\ \text{N/C}$ .

7 0

3 years ago