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BabaBlast [244]
3 years ago
15

If you make multiple measurements of your height, you are likely to find that the results vary by nearly half an inch in either

direction due to measurement error and actual variations in height. You are slightly shorter in the evening, after gravity has compressed and reshaped your spine over the course of a day. One measurement of a man's height is 5 feet and 7 inches.
Physics
1 answer:
Lisa [10]3 years ago
8 0

Answer:

Height h= 1.7 m

Explanation:

Supposing we have to find height in meter.

1 feet = 0.3048 m

1 inch = 0.0254 m

Given that:

5 feet

= 5×0.3048

= 1.524 m

and 7 inch = 7×0.0254= 0.1778 m

Therefore total height of a man in meter

5 feet 7 inch = 1.5424+0.1778 =1.7 m

Height h= 1.7 m

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Answer:

The ram has done more work because the rate at which the ram work is 1.6m/s and Hari is 1.1m/s

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Hulk starts at -2 m, jumps to -15 m, and settles at 6 m. What is Hulk's displacement?
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Answer:

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a bullet moving with a velocity of 100m/s pierce a block of wood and moves out with a velocityof 10 m/s.if the thickness of the
erma4kov [3.2K]

The emerging velocity of the bullet is <u>71 m/s.</u>

The bullet of mass <em>m</em> moving with a velocity <em>u</em>  has kinetic energy. When it pierces the block of wood, the block exerts a force of friction on the bullet. As the bullet passes through the block, work is done against the resistive forces exerted on the bullet by the block. This results in the reduction of the bullet's kinetic energy. The bullet has a speed <em>v</em> when it emerges from the block.

If the block exerts a resistive force <em>F</em> on the bullet and the thickness of the block is <em>x</em> then, the work done by the resistive force is given by,

W=Fx

This is equal to the change in the bullet's kinetic energy.

W=Fx=\frac{1}{2} m(u^2-v^2)......(1)

If the thickness of the block is reduced by one-half, the bullet emerges out with a velocity v<em>₁.</em>

Assuming the same resistive forces to act on the bullet,

F(\frac{x}{2} )=\frac{1}{2} m(u^2-v_1^2)......(2)

Divide equation (2) by equation (1) and simplify for v<em>₁.</em>

\frac{\frac{Fx}{2} }{Fx} =\frac{(u^2-v_1^2)}{(u^2-v^2)} \\\frac{100^2-v_1^2}{100^2-10^2} =\frac{1}{2} \\v_1^2=5050\\v_1=71.06 m/s

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3 0
3 years ago
What principle of joint operations entails expending minimum essential combat power on secondary efforts in order to allocate th
iVinArrow [24]
The principle of  joint operations that entails expending minimum essential combat power on secondary efforts in order to allocate the maximum possible combat power on primary efforts is called the economy of force. It is one of the principles of war that is based on Clausewitz's approach.  The economy of force is the principle where we employ all of the available combat power in a way that is the most effective as much as possible, attempting to allocate a least amount of important combat power to any efforts. It is closely associated to the idea of force concentration. According to this principle, any part of the whole effort should not be left idle.
8 0
3 years ago
A coil of conducting wire carries a current of i(t) = 14.0 sin(1.15 ✕ 103t), where i is in amperes and t is in seconds. A second
Advocard [28]

Answer:

The peak emf in second coil is 1.876 V

Explanation:

Given :

Inductance L = 130 \times 10^{-6} H

The current I(t) = 14 \sin(1.15\times 10^{3} t)

We compare above equation with standard equation,

  I(t) = I_{o} \sin (\omega t + \phi)

From above equation we have,

  \omega = 10^{3} and \phi = 1.15

Find the inductive resistance,

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  X_{L} = 0.134

The peak emf in second coil is,

   V = I_{o} X_{L}

  V = 14 \times 0.134

  V = 1.876 V

Therefore, the peak emf in second coil is 1.876 V

8 0
3 years ago
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