The force needed to keep the space shuttle moving at constant speed is 0.
The given parameters;
- <em>weight of the space shuttle, F = 750,000 N</em>
- <em>constant speed of the space shuttle, v = 28,000 km/h</em>
The mass of the space shuttle is calculated as follows;
The force needed to keep the space shuttle moving at constant speed is calculated as follows;
where;
a is the acceleration of the space shuttle
At a constant speed, acceleration is zero.
F = 76,530.61 x 0
F = 0
Thus, the force needed to keep the space shuttle moving at constant speed is 0.
Learn more here:brainly.com/question/16374764
<h2>
Speed of motorboat is 36 km/hr and speed of current is 4 km/hr.</h2>
Explanation:
Let speed of motor boat be m and speed of current be c.
A motorboat traveling with a current can go 160 km in 4 hours.
Distance = 160 km
Time = 4 hours
Speed = m + c
We have
Distance = Speed x Time
160 = (m+c) x 4
m + c = 40 --------------------- eqn 1
Against the current it takes 5 hours to go the same distance.
Distance = 160 km
Time = 5 hours
Speed = m - c
We have
Distance = Speed x Time
160 = (m-c) x 5
m - c = 32 --------------------- eqn 2
eqn 1 + eqn 2
2m = 40 + 32
m = 36 km/hr
Substituting in eqn 1
36 + c = 40
c = 4 km/hr
Speed of motorboat is 36 km/hr and speed of current is 4 km/hr.
Answer:
The maximum velocity is 0.377 m/s
Explanation:
Please, the solution is in the Word file attached
Solar system is the gravitationally bound system that consists of the sun and the objects that orbit around it directly or indirectly. These objects includes the planets which orbit the sun directly an other small objects such as meteoroids, asteroids, satellites of the planets and numerous comets. The sun makes up most of the solar system' mass.
(a) 3.56 m/s
(b) 11 - 3.72a
(c) t = 5.9 s
(d) -11 m/s
For most of these problems, you're being asked the velocity of the rock as a function of t, while you've been given the position as a function of t. So first calculate the first derivative of the position function using the power rule.
y = 11t - 1.86t^2
y' = 11 - 3.72t
Now that you have the first derivative, it will give you the velocity as a function of t.
(a) Velocity after 2 seconds.
y' = 11 - 3.72t
y' = 11 - 3.72*2 = 11 - 7.44 = 3.56
So the velocity is 3.56 m/s
(b) Velocity after a seconds.
y' = 11 - 3.72t
y' = 11 - 3.72a
So the answer is 11 - 3.72a
(c) Use the quadratic formula to find the zeros for the position function y = 11t-1.86t^2. Roots are t = 0 and t = 5.913978495. The t = 0 is for the moment the rock was thrown, so the answer is t = 5.9 seconds.
(d) Plug in the value of t calculated for (c) into the velocity function, so:
y' = 11 - 3.72a
y' = 11 - 3.72*5.913978495
y' = 11 - 22
y' = -11
So the velocity is -11 m/s which makes sense since the total energy of the rock will remain constant, so it's coming down at the same speed as it was going up.
