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3 years ago

When is an element neutral?

Physics

2 answers:

Svet_ta [14]3 years ago

5 0

When it has an equal number of positive and negative particles

zlopas [31]3 years ago

4 0

When there is an equal part of positive particles and negatives particles.

Good Studying !

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A colorless liquid is located in a graduated cylinder that measures 35 mL. If the graduated cylinder has a mass o

Alchen [17]

Density of liquid is 1 g/mL.

<h3>What is density of a substance?</h3>

Density is the ratio of the mass and the volume of a substance

Mathematically density of a substance is given as follows:

Density = mass/volume

The density of the substance is:

mass of liquid = 172 - 137 = 35 g

volume of liquid = 35 mL

Density of liquid = 35 g/35 mL

Density of liquid = 1 g/mL

In conclusion, density is obtained as a ratio of mass and volume.

Learn more about density at: brainly.com/question/1354972

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3 0

2 years ago

• 500 waves pass by in 2 second. These waves have a wavelength of 6

tamaranim1 [39]

Answer:

6/2times500=1500

Explanation:

s = d/t which means speed equals distance divided by time.

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3 years ago

True or False: The medium moves up and down in a transverse wave.

kicyunya [14]

False ...................

4 0

3 years ago

Erik Erikson’s theory of psychosocial development emphasizes that development occurs by overcoming an emotional crisis in each o

lorasvet [3.4K]

Answer:

True

Explanation:

8 0

2 years ago

The speed of an arrow fired from a compound

san4es73 [151]

Answer:

A.) The arrow`s range is 624,996 m

B.) The arrow`s range is 846.887 m, when the horse is galloping

Explanation:

We have a case of oblique movement. In these cases the movement in the X axis is a Uniform Rectelinear Movement (URM), and a Uniform Accelerated Movement (UAM) in the Y axis.

By the way, the equations that we use for the X axis will be from URM, and those for the Y axis wiil be from UAM.

<u>Equations</u>

X axis:

$X=v_{ox}*t$

$v_{0x} =v_0cos(\alpha)$

Y axis:

$Y= Y_0 +v_{y0} t - \frac{g}{2} t^2$

A.) First, it is necessary to know t, total time.

To figure out t value, we use UAM, since time is determined by this movement.

Now, at the end of the movement, $Y=0$ , then

$0= Y_0 +v_{y0} t - \frac{g}{2} t^2$

$0=2.4m+79m/s*sin(39)t-(1/2*9.81m/s^2)t^2$

Caculate the segcond degree equation to obtain the two possible values for t:

$t_1= 10.18 \\t_2= -0.04046$

But, in physics, time it could not be negative, so we take $t_1= 10.18$

Caculate now:

$X=79m/s*cos(\39)*10.18s= 624.996 m$

B.) Now, the narrow has an additional speed, that could be sum to the speed due to the bow.

$v_0= 79m/s+13m/s= 92m/s$

Using the same procedure that item A, caculate X

First, we need to know the new time

$0=2.4m+92m/s*sin(39)t-(1/2*9.81m/s^2)t^2$

And we obtain:

$t_1=11.845s\\t_2=-0.041s$

One more time, we take the positive time: $t_1=11.845s$

Finally:

$X=92m/s *cos(39)*11.845s=846.887 m$

6 0

3 years ago