Answer:
Hygroscopic
Explanation:
An hygroscopic substance is one that absorbs moisture from the atmosphere and becomes wet. Their ability to remove water from air is less than that of deliquescent substances. Most of the solid hygroscopic substances forms pasty substances and not solutions like the deliquescent compounds.
Examples are sodium trioxonitrate(v), copper(ii) oxide e.t.c
Efflorescence compounds gives off their water of crystallization to the atmosphere.
To calculate the amount of heat transferred when an amount of reactant is decomposed, we must look at the balanced reaction and its corresponding heat of reaction. In this case, we can see that 252.8 kJ of heat is transferred per 2 moles of CH3OH used. When 22 g of CH3OH is used, 86.9 kJ is absorbed.
Answer:
Alkyne
Explanation:
The homologous series for this compound is the Alkyne because of the presence of the triple bond present between the third and fourth carbon atoms as seen in the picture attached.
<u>Answer:</u> The uncertainty in the velocity of oxygen molecule is ![4.424\times 10^{-5}m/s](https://tex.z-dn.net/?f=4.424%5Ctimes%2010%5E%7B-5%7Dm%2Fs)
<u>Explanation:</u>
The diameter of the molecule will be equal to the uncertainty in position.
The equation representing Heisenberg's uncertainty principle follows:
![\Delta x.\Delta p=\frac{h}{2\pi}](https://tex.z-dn.net/?f=%5CDelta%20x.%5CDelta%20p%3D%5Cfrac%7Bh%7D%7B2%5Cpi%7D)
where,
= uncertainty in position = d = ![4.50\times 10^{-5}m](https://tex.z-dn.net/?f=4.50%5Ctimes%2010%5E%7B-5%7Dm)
= uncertainty in momentum = ![m\Delta v](https://tex.z-dn.net/?f=m%5CDelta%20v)
m = mass of oxygen molecule = ![5.30\times 10^{-26}kg](https://tex.z-dn.net/?f=5.30%5Ctimes%2010%5E%7B-26%7Dkg)
h = Planck's constant = ![6.627\times 10^{-34}kgm^2/s^2](https://tex.z-dn.net/?f=6.627%5Ctimes%2010%5E%7B-34%7Dkgm%5E2%2Fs%5E2)
Putting values in above equation, we get:
![4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 4.50\times 10^{-5}m\times 5.30\times 10^{-26}kg}=4.424\times 10^{-5}m/s](https://tex.z-dn.net/?f=4.50%5Ctimes%2010%5E%7B-5%7Dm%5Ctimes%205.30%5Ctimes%2010%5E%7B-26%7Dkg%5Ctimes%20%5CDelta%20v%3D%5Cfrac%7B6.627%5Ctimes%2010%5E%7B-34%7Dkgm%5E2%2Fs%7D%7B2%5Ctimes%203.14%7D%5C%5C%5C%5C%5CDelta%20v%3D%5Cfrac%7B6.627%5Ctimes%2010%5E%7B-34%7Dkgm%5E2%2Fs%5E2%7D%7B2%5Ctimes%203.14%5Ctimes%204.50%5Ctimes%2010%5E%7B-5%7Dm%5Ctimes%205.30%5Ctimes%2010%5E%7B-26%7Dkg%7D%3D4.424%5Ctimes%2010%5E%7B-5%7Dm%2Fs)
Hence, the uncertainty in the velocity of oxygen molecule is ![4.424\times 10^{-5}m/s](https://tex.z-dn.net/?f=4.424%5Ctimes%2010%5E%7B-5%7Dm%2Fs)
Answer:
An Educated Guess
Explanation:
After the scientist is done with the experiment he should do an educated guess, they use the data from the experiments to make charts and graphs to communicate the results of the experiment. After the scientists makes the hypothesis, they perform this procedure.