All categories

3 years ago

What is the mass of a object if it occupies a volume of 3.10 cm and has a density of 2.7 g/cm

Chemistry

1 answer:

irinina [24]3 years ago

8 0

Answer:

8.37

Explanation:

mass= volume x density

You might be interested in

A chunk of ice breaks off a glacier and falls 30.0 m before it hits the water. Assuming it falls freely (there is no air resista

lina2011 [118]

Answer:

The ice chunk will take 2.47 seconds to hit the water.

Explanation:

Height from which ice chunk fell = h = 30.0 m

Initial velocity of the ice chunk = u = 0 m/s

Time taken by ice chunk to cover 30.0 m of height = t

Acceleration due to gravity = g $9.8m/s^2$

Using second equation of motion ;

$h=ut+\frac{1}{2}gt^2$

$30.0 m=0 m/s\times t+\frac{1}{2}\times 9.8 m/s^2\times t^2$

$t=\sqrt{\frac{30.0m/s\times 2}{9.8 m/s^2}}2.47 s$

The ice chunk will take 2.47 seconds to hit the water.

7 0

2 years ago

Zinc and sulfuric acid solution produce zinc sulfate solution and hydrogen balanced chemical equation

IRISSAK [1]

Answer:

Zn + H2SO4 → ZnSO4 + H. 2

Explanation:

8 0

3 years ago

In which part of a plant cell does photosynthesis occur?

IrinaVladis [17]

Answer:

<h2>leaves,</h2>

Hope it helps....⋋✿ ⁰ o ⁰ ✿⋌(・o・)

6 0

2 years ago

Read 2 more answers

Our solar system formed from a

ankoles [38]

Our solar system formed about 4.5 billion years ago from a dense cloud of interstellar gas and dust. The cloud collapsed most likely due to a shockwave form a nearby exploding start called a supernova

8 0

2 years ago

Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi

AlexFokin [52]

Explanation:

The given cell reaction is as follows.

$In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)$

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : $In(s) \rightarrow In^{3+}(aq) + 3e^{-}$ ...... (1)

At cathode; Reduction-half reaction : $Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s)$ ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

$2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}$

$3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)$

Net reaction: $2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

Thus, we can conclude that the overall cell reaction is as follows.

$2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)$

4 0

2 years ago