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2 years ago

5. How many moles of NaCl will it take to make 3.0 L of a 0.1 M solution?

Chemistry

1 answer:

Ilia_Sergeevich [38]2 years ago

8 0

Answer:

0.30 mole NaCl needed.

Explanation:

From the definition of solution molarity => Molarity = moles solute / Volume of Solution in Liters => Molarity = moles/Volume(L) => solve for moles =>

moles = Molarity X Volume(L) = (0.1M)(3.0L) = 0.30 mole NaCl needed.

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Answer:

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Explanation:

The balanced chemical equation is:

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Now, standard values of $\Delta H_f\ of\ all\ participants\ of\ reaction.$

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Now, We know $\Delta H_{rxn}=\Delta H_{products}-\Delta H_{reactants}$

Putting all values of $\Delta H_f$ to above equation.

We get,

$\Delta H_{rxn}=-847.6\ KJ/mol.$

Hence, this is the required solution.

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