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Sedbober [7]
3 years ago
9

The goal of this lesson is to answer the lesson question, "what does half-life ‘look like' for a radioactive substance?" fill in

the blanks to complete the hypothesis. hypothesis: if an element is radioactive, then the fraction of radioactive remaining after n half-life cycles should be approximately n because…
Chemistry
2 answers:
Serggg [28]3 years ago
6 0

The half life for radioactive can be calculated as:

N /N0 = (1 /2) ^ n

n = T /T half

According to question there are n number of half life are present which would result in remaining amount of element as n.

disa [49]3 years ago
5 0

Atoms

0.5

There are n number of half life are present which would result in remaining amount of element as n.


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Two solutions, initially at 24.60 °C, are mixed in a coffee cup calorimeter (Ccal = 15.5 J/°C). When a 100.0 mL volume of 0.100
yulyashka [42]

Answer:

ΔH = -59.6kJ/mol

Explanation:

The reaction that occurs between Ag⁺ and Cl⁻ ions is:

Ag⁺ + Cl⁻ → AgCl(s) + ΔH

To find ΔH we need to obtain moles of reaction and heat released in the reaction because ΔH is defined as heat released per mole of reaction.

<em>Moles of reaction:</em>

Moles of Ag⁺ and Cl⁻ added are:

Ag⁺: 0.100L * (0.100mol / L) = 0.01moles

Cl⁻: 0.100L * (0.200mol / L) 0 0.02 moles

That means limiting reactant is Ag⁺ and moles of reaction are 0.01 moles

<em>Heat released:</em>

To find heat released we must use coffe cup calorimeter equation:

Q = C*m*ΔT

<em>Where C is specific heat of solution (4.18J/g°C), m is the mass of solution (200g because there are 100 + 100mL = 200mL and density of solution is 1g/mL) and ΔT is change in temperature (25.30°C - 24.60°C = 0.70°C).</em>

Replacing:

Q = C*m*ΔT

Q = 4.18J/g°C * 200g * 0.70°C

Q = 585,2J

Is total heat released.

The calorimeter absorbs:

15.5J / °C * 0.7°C = 10.85

Thus, when 0.01 moles reacts, 585.2J + 10.85  = 596.05J are released (Heat released is heat abosrbed by calorimeter + Heat absorbed by water) and ΔH is:

ΔH = 596.05J / 0.01 moles =

ΔH = 59605J / mol =

<h3>ΔH = -59.6kJ/mol</h3>

<em>As heat is released, ΔH < 0.</em>

6 0
3 years ago
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ollegr [7]

Answer:

what

Explanation:

3 0
2 years ago
Read 2 more answers
Charles's law is an experimental gas law that shows the relationship between the temperature of a gas and its corresponding volu
iren [92.7K]

Answer:

The correct answer is (b)

Explanation:

Charles law describes the behavior of gases when heated. Charles law states that the volume of a given mass of gas would increase as its Kelvin temperature increases provided the pressure is held constant. That is the volume of a given mass of gas is directly proportional to its Kelvin temperature at constant pressure

3 0
3 years ago
Which material cannot be made into a magnet ?
bogdanovich [222]
<span>Its b.aluminum 

I hope this helps and sorry if I am wrong </span>
7 0
2 years ago
Read 2 more answers
What is the edge length of a face-centered cubic unit cell that is made of of atoms, each with a radius of 154 pm
gladu [14]

Answer:

The edge length of a face-centered cubic unit cell is 435.6 pm.

Explanation:

In a face-centered cubic unit cell, each of the eight corners is occupied by one atom and each of the six faces is occupied by a single atom.

Hence, the number of atoms in an FCC unit cell is:

8*\frac{1}{8} + 6*\frac{1}{2} = 4 atoms

In a face-centered cubic unit cell, to find the edge length we need to use Pythagorean Theorem:

a^{2} + a^{2} = (4R)^{2}     (1)

Where:

a: is the edge length

R: is the radius of each atom = 154 pm      

By solving equation (1) for "a" we have:

a = 2R\sqrt{2} = 2*154 pm*\sqrt{2} = 435.6 pm    

Therefore, the edge length of a face-centered cubic unit cell is 435.6 pm.   

I hope it helps you!

7 0
3 years ago
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