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Sedbober [7]
3 years ago
9

The goal of this lesson is to answer the lesson question, "what does half-life ‘look like' for a radioactive substance?" fill in

the blanks to complete the hypothesis. hypothesis: if an element is radioactive, then the fraction of radioactive remaining after n half-life cycles should be approximately n because…
Chemistry
2 answers:
Serggg [28]3 years ago
6 0

The half life for radioactive can be calculated as:

N /N0 = (1 /2) ^ n

n = T /T half

According to question there are n number of half life are present which would result in remaining amount of element as n.

disa [49]3 years ago
5 0

Atoms

0.5

There are n number of half life are present which would result in remaining amount of element as n.


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Consider a mixture of NaCl and NaNO3 that is 31.8% Na by mass. Calculate the percentage by mass of NaCl in the mixture.
lutik1710 [3]

<u>Answer:</u> The percentage by mass of NaCl in the mixture is 38.5 %

<u>Explanation:</u>

To calculate the mass percentage of element in compound, we use the equation:

\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100      .......(1)

  • <u>For NaCl:</u>

Mass of sodium element = 23 g

Mass of NaCl = 58.5 g

Putting values in equation 1, we get:

\text{Mass percent of sodium element}=\frac{23g}{58.5g}\times 100=39.32\%

Mass fraction of sodium metal in NaCl = 0.3932

  • <u>For NaNO_3 :</u>

Mass of sodium element = 23 g

Mass of NaNO_3 = 85 g

Putting values in equation 1, we get:

\text{Mass percent of sodium element}=\frac{23g}{85g}\times 100=27.1\%

Mass fraction of sodium metal in sodium nitrate = 0.271

Let us assume the mass fraction of NaCl in the mixture is 'x'

So, the mass fraction of NaNO_3 in the mixture will be '(1-x)'

We are given:

Percent by mass of Na in the mixture = 31.8 %

Mass fraction of Na in the mixture = 0.318

Evaluating the mass fraction of NaCl in the mixture:

[(x\times 0.3932)+((1-x)\times 0.271)]=0.318

x = 0.385

Percent by mass of NaCl in the mixture will be = (0.385\times 100)=38.5\%

Hence, the percentage by mass of NaCl in the mixture is 38.5 %

4 0
3 years ago
Why is specific activity used as a measurement of enzyme purity, but the turnover number cannot be used for this purpose?
Lelechka [254]

Answer:

See explanation

Explanation:

Specific activity of an enzyme is defined as a measure of the rate of reaction between enzyme and substrate.

In the study of enzyme kinetics, specific activity is particularly regarded to be the amount of substrate converted by the enzyme per milligram of protein per unit of time. It is thus a reliable measure of enzyme activity per milligram of total protein.

On the other hand, the turnover number is defined as a measure of the number of conversions achieved by a substrate molecule in one second at a particular active site depending on the specific enzyme concentration.

Since specific activityof the enzyme is the ratio of the enzyme activity to enzyme concentration, then specific activity can be used as a measurement of enzyme purity.

4 0
3 years ago
Which of the following reactions could be used to power a battery because of the transfer of electrons?
Trava [24]

Answer is: Zn + Cu2+ → Zn2+ + Cu.

In this chemical reaction, there is transfer of electrons from zinc (Zn) to copper (Cu). Zinc change oxidation number from 0 to +2 (lost electrons) and copper change oxidation number from +2 to 0 (gain electrons).

Oxidation half reaction: Zn⁰ → Zn²⁺ + 2e⁻.

Reduction half reaction: Cu²⁺ + 2e⁻ → Cu⁰.

In other chemical reactions, there is no change of oxidation number of elements.

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Just be nice, and compliment her
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3 years ago
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Isotope b has a half-life of 3 days. a scientist measures out 100 grams of this substance. after 6 days has passed, the scientis
Brilliant_brown [7]
So half life is the time taken for a sample to decay to half its original mass, its a constant and applies to any original mass, it could be 5g or 1kg, it will take the same amount of time for the original mass to half. In this case the half life is 3 days.

After 3 days the sample will be at half its original mass, now 50g. 

Now we can treat the 50g as if its a new sample. After another 3 days (6 days in total) there will be half of 50g left, = 25g. 


6 0
3 years ago
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