The goal of this lesson is to answer the lesson question, "what does half-life ‘look like' for a radioactive substance?" fill in
2 answers:
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Answer:
7.32g of HNO3 are required.
Explanation:
1st) From the balanced reaction we know that 2 moles of HNO3 react with 1 mole of Ca(OH)2 to produce 2 moles of H2O and 1 mole of Ca(NO3)2.
From this, we find that the relation between HNO3 and Ca(OH)2 is that 2 moles of HNO3 react with 1 mole of Ca(OH)2.
2nd) This is the order of the relations that we have to use in the equation to calculate the grams of nitric acid:
• starting with the 4.30 grams of Ca(OH)2.
,• using the molar mass of Ca(OH)2 (74g/mol).
,• relation of the 2 moles of HNO3 that react with 1 mole of Ca(OH)2 .
,• using the molar mass of HNO3 (63.02g/mol).
So, 7.32g of HNO3 are required.
464 g radioisotope was present when the sample was put in storage
<h3>Further explanation</h3>Given
Sample waste of Co-60 = 14.5 g
26.5 years in storage
Required
Initial sample
Solution
General formulas used in decay:
t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
Half-life of Co-60 = 5.3 years
Input the value :