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galben [10]
3 years ago
10

Round 264.23 to 3 sig figs

Chemistry
1 answer:
Darya [45]3 years ago
3 0

Answer:

264

Explanation:

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3 years ago
Calculate the hydrogen-ion concentration [H+] for the aqueous solution in which [OH–] is 1 x 10–11 mol/L. Is this solution acidi
valina [46]
(H+)(OH-) = Kw
kw=  1 x10^-14
OH-=  1   x10 ^-11
(H+)=  KW / OH-

concentration   of H+  = (1x10^-14) /.(1  x 10 ^-11)   =  1  x10  ^-3

Ph=  -log (H+)

PH=-log (  1  x  10  ^-3)  =  3  therefore  the    solution  is  acidic  since  the  PH   less than  7

7 0
3 years ago
A strong acid like hcl _____.a strong acid like hcl _____.dissociates completely in an aqueous solutionis a strong buffer at low
vladimir2022 [97]
Answer: A strong acid like HCl dissociates completely in an aqueous solution.

By definition a strong acid is that that dissociates completely in aqueous solutions. That means that all the molecules of the acid will be inoized into hydronium cation (H3O+) and anion (the negative radical).

For expample, HCl is a strong acid because

HCl + H2O----> H3O(+) + Cl-

The forwar arrow indicates that all the molecules of HCl reacted with the water for form the ions.
4 0
3 years ago
Explain why the ability of PLP to catalyze an amino acid transformation is greatly reduced if the OHOH substituent of pyridoxal
cupoosta [38]

Answer:

Following are the responses to the given question:

Explanation:

In the given question the OH could be generated as the H-bond with both the N (nitrogen), which is used to place its N as the partially positive value(+). It is used to simplifies the addition for either its  AA with the imine C. In the above H-bond, the w N is not required as the possibility to use the OCH3

7 0
2 years ago
In an acid-base neutralization reaction 43.74 ml of 0.500 m potassium hydroxide reacts with 50.00 ml of sulfuric acid solution.
timama [110]
The   neutralization reaction between  potassium  hydroxide  and  sulfuric  acid   is  as  follows
2KOH  +  H2SO4 ---> K2SO4  +  2H2O

number  of   moles  of  KOH=  (43.74  x  0.500)/  1000=  0.02187 moles

the  reacting ratio  of  KOH  to H2SO4  is  2:1  therefore  the   moles  of  H2SO4  is  =  0.021187/2=  0.01094 moles

concentration(molarity) = ( 0.01094/50 ) x 1000=  0.2188M
7 0
3 years ago
Read 2 more answers
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