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xxTIMURxx [149]

2 years ago

6

This table shows the area in inches of four rectangular scraps of fabric.

1 answer:

Fittoniya [83]2 years ago

8 0

Answer: 82

Step-by-step explanation:

(80+ 84) / 2

164/2

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Find x <br> Plz help me !!!

mel-nik [20]

Answer:

$\Huge\boxed{x=33.2}$

Step-by-step explanation:

Hello there!

We can solve for x using law of sines

As we can see in the image a side length divided by sin ( its opposite angle) = a different side length divided by sin ( its opposite angle)

So we can use this equation to solve for x

$\frac{21}{sin(35)} =\frac{x}{sin(65)}$

Our objective is to isolate the variable using inverse operations so to get rid of sin (65) we multiply each side by sin (65)

$\frac{x}{sin(65)} sin(65)=x\\\\\frac{21}{sin(35)} sin(65)=\frac{21sin(65)}{sin(35)}$

we're left with

$x=\frac{21sin(65)}{sin(35)}\\x=33.18208755$

assuming we have to round the answer would be 33.18 or 33.2

7 0

2 years ago

What is the standard form of the number three million sixty thousand five hundred twenty

Serga [27]

3,060,520
3,060,520
3,060,520

3 0

2 years ago

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Find the HCF of 20,55,90<br> Pls help it is urgent if i dont get this answer i will fail

Ann [662]

Answer:

Step-by-step explanation:

Factors of 20 = 1 2 4 5 10 20

Factors of 55 = 1 5 11 55

Factors of 90 = 1 2 3 5 6 9 10 15 18 30 45 90

Hcf = 5

5 0

2 years ago

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago

Help me? Math again..

Dmitry [639]

Each lollipop is approximately 49 cents because if you take the total cost and divide it by the quantity you get 0.499

8 0

2 years ago

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