3 years ago

HELP!! I got a few mins left

Mathematics

1 answer:

Oxana [17]3 years ago

7 0

Answer:

Hey friend,Sorry because Idk about the others but about question 7, the correct answer according to me is Option C: x<4. Sorry because Idk about the others.

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goblinko [34]

Answer:

Hi,

a=b+3

Step-by-step explanation:

$\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&c-a-b-1\\\end{array}$

$\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=2&&2&4-2a&2b+8-4a\\---&---&---&---&---\\&1&2-a&b+4-2a&c+2b+8-4a\\\end{array}$

Thus:

c+2b+8-4a=c-a-b-1

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--------------------

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