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blagie [28]
3 years ago
10

Complete this equation that represents the process of nuclear fission

Physics
2 answers:
ElenaW [278]3 years ago
5 0

Answer:

A: 146

B: 56

Explanation:

edge

r-ruslan [8.4K]3 years ago
4 0

Answer: A - 146

B - 56

Explanation:

right on edg

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Select the correct answer.
lutik1710 [3]
I’m sorry i haven’t found the answer to this
8 0
3 years ago
Solar evaporation ponds are shallow so that the sun can heat them up, causing the water to evaporate, which increases the salt c
ehidna [41]

Answer:

B. stearothermophilus and S. ruber

Explanation:

B. stearothermophilus and S. ruber

In solar evaporation ponds the temperature is higher and the salt concentration is also higher because of the water evaporated so sunder such extreme conditions this hybrid bacteria is capable of surviving. B. stearothermophilus is thermophilus bacteria which grows at high temperature and S. ruber is halophilic bacteria which grows in saline environment. So, these two bacteria best suited for the above hybrid condition.

6 0
3 years ago
A 1800-kg Jeep travels along a straight 500-m portion of highway (from A to B) at a constant speed of 10 m/s. At B, the Jeep enc
vladimir1956 [14]

Answer:

3600N

Explanation:

F=m\frac{v^2}{r}

4 0
3 years ago
An open organ pipe 30 cm long and a closed organ pipe 23 cm long, both of same diameter , are each sounding its first overtone ,
cupoosta [38]

First overtone of open organ pipe is given as

f_{1o} = \frac{v}{L_1 + 2e}

first overtone of closed organ pipe is given as

f_{1c} = \frac{3v}{4(L_2 + e)}

now they are in unison so we will have

\frac{v}{L_1 + 2e} = \frac{3v}{4(L_2 + e)}

\frac{1}{30 + 2e} = \frac{3}{4(23 + e)}

90 + 6e = 92 + 4e

e = 1 cm

so end correction of both pipes is e = 1 cm

8 0
3 years ago
Use the SI prefixes in Table 3 of this chapter to convert these hypothetical units of measure into appropriate quantities: a. 10
8090 [49]
A. 10 rations = 1 deca-ration.

b. 2000 mockingbirds = 2 x 10³ = 2 kilo-mockingbirds.

c. 10⁻⁵ phones = 1 micro-phones.

d. 10⁻⁹ goats = 1 nano-goats.

e. 1018 miners = 1.018 x 10³ = 1.018 kilo-miners.
4 0
3 years ago
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