In science, a hypothesis must be true.

Tarnish is produced by a redox reaction that occurs when a metal reacts with

Dvinal [7]

Answer:

Copper atoms lose electrons to sulfur atoms

Explanation:

a p e x (:

6 0

2 years ago

A solenoid 0.425 m long has 950 turns of wire. What is the magnetic field in the center of the solenoid when it carries a curren

lesya692 [45]

Answer:

The magnetic field in the center of the solenoid is $7.8\times10^{-3}\ T$ .

Explanation:

Given that,

Length of solenoid = 0.425 m

Number of turns N = 950

Current I = 2.75 A

The magnetic field in the center of the solenoid is the product of the current , number of turns per unit length and permeability.

In mathematical form,

$B = \mu_{0}nI$

Where, $n = \dfrac{N}{l}$

N = number of turns

L = length

I = current

Now, The magnetic field

$B = \dfrac{\mu_{0}NI}{l}$

Put the value into the formula

$B=\dfrac{4\pi\times10^{-7}\times950\times2.75}{0.425}$

$B=\dfrac{4\times3.14\times10^{-7}\times950\times2.75}{0.425}$

$B=7.8\times10^{-3}\ T$

Hence, The magnetic field in the center of the solenoid is $7.8\times10^{-3}\ T$ .

4 0

2 years ago

a 2.0 kg block slides on the horizontal, frictionless surface until it counters a spring force constant with

icang [17]

Complete question:

a 2.0 kg block slides on the horizontal, frictionless surface until it counters a spring with force constant of 955 N/m. The block comes to rest after compressing the spring a distance of 4.6 cm. Find the initial speed (in m/s) of the block.

Answer:

The initial speed of the block is 1.422 m/s

Explanation:

Given;

mass of the block, m = 2.0 kg

force constant of the spring, K = 955 N/m

compression of the spring, x = 4.6 cm = 0.046 m

Apply Hook's law to determine applied force on the spring;

F = Kx

F = (955 N/m)(0.046 m)

F = 43.93 N

Apply Newton's 2nd law to determine the magnitude of deceleration of the block when it encounters the spring;

F = ma

a = F / m

a = 43.93 / 2

a = 21.965 m/s²

Apply kinematic equation to determine the initial speed of the block;

v² = u² + 2ax

where;

v is the final speed of the block = 0

u is the initial speed of the block

x is the distance traveled by the block = compression of the spring

a is the block deceleration = -21.965 m/s²

0 = u² + 2(-21.965 )(0.046)

0 = u² - 2.021

u² = 2.021

u = √2.021

u = 1.422 m/s

Therefore, the initial speed of the block is 1.422 m/s

8 0

2 years ago

Sort the processes based on the type of energy transfer they involve.??

klemol [59]

The 1st one goes two added sodoes the second one then the third goes to removed then the fourth goes to added and the rest go to removed

3 0

2 years ago

Read 2 more answers

Two particles each have the same mass but particle #1 has four times the charge of particle #2. Particle #1 is accelerated from

marin [14]

Answer:

v_2 = 2*v

Explanation:

Given:

- Mass of both charges = m

- Charge 1 = Q_1

- Speed of particle 1 = v

- Charge 2 = 4*Q_1

- Potential difference p.d = 10 V

Find:

What speed does particle #2 attain?

Solution:

- The force on a charged particle in an electric field is given by:

F = Q*V / r

Where, r is the distance from one end to another.

- The Net force acting on a charge accelerates it according to the Newton's second equation of motion:

F_net = m*a

- Equate the two expressions:

a = Q*V / m*r

- The speed of the particle in an electric field is given by third kinetic equation of motion.

v_f^2 - v_i^2 = 2*a*r

Where, v_f is the final velocity,

v_i is the initial velocity = 0

v_f^2 - 0 = 2*a*r

Substitute the expression for acceleration in equation of motion:

v_f^2 = 2*(Q*V / m*r)*r

v_f^2 = 2*Q*V / m

v_f = sqrt (2*Q*V / m)

- The velocity of first particle is v:

v = sqrt (20*Q / m)

- The velocity of second particle Q = 4Q

v_2 = sqrt (20*4*Q / m)

v_2 = 2*sqrt (20*Q / m)

v_2 = 2*v

3 0

2 years ago