Question

An object with mass M is attached to the end of a string and is raised vertically at a constant acceleration of g 10 . If it has been raised a distance ℓ from rest, how much work has been done by the tension in the string?

Answer 1

Answer:

Work done against gravity will be

W = Mgℓ

Explanation:

Work done to raise the mass from ground to given height is against gravity

So here work done is given by the formula

$W = F.d$

here we know that

$F = Mg$

it is the force due to gravity which is also known as weight

so here distance moved by the object is given as

d = ℓ

now work done is given as

W = Mg ℓ

Answer 2

The work by tension is ¹¹/₁₀ Mgℓ

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Further explanation

Complete Question:

An object with mass M is attached to the end of a string and is raised vertically at a constant acceleration of g/10 . If it has been raised a distance ℓ from rest, how much work has been done by the tension in the string?

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Given:

Mass of the object = M

Acceleration of the object = g/10

Distance = ℓ

Asked:

Work by Tension = W = ?

Solution:

Let's find the magnitude of tension as follows:

$\Sigma F = ma$

$T - Mg = Ma$

$T = Mg + Ma$

$T = M(g + a)$

$T = M(g + \frac{1}{10}g)$

$T = M(\frac{11}{10}g)$

$T = \frac{11}{10}Mg$

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$W = T \times L$

$W = \frac{11}{10}Mg \times L$

$W = \frac{11}{10}MgL$

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The work by tension is ¹¹/₁₀ Mgℓ

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Learn more

• Impacts of Gravity : brainly.com/question/5330244
• Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
• The Acceleration Due To Gravity : brainly.com/question/4189441
• Newton's Law of Motion: brainly.com/question/10431582
• Example of Newton's Law: brainly.com/question/498822

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Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant