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Wittaler [7]
3 years ago
12

NaCl is common table salt and is an ionic compound. Table salt can be stirred into water to create a salt-water solution. What h

appens to the solubility of sodium chlorate, NaClO3, as the temperature of the water rises?
Physics
2 answers:
Paha777 [63]3 years ago
7 0
Loouud is the best four you too be proud

fgiga [73]3 years ago
3 0
The answer is A.  they increase
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Be easy-going and be yourself.

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Why are Mars and Europa the top targets for the study of astrobiology?
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The natural satelite Europa and the planet Mars are the two rock systems more likely to earth on their conditions all about solar system. Europa has a huge liquid water ocean and temperature is pretty similar to earth, Mars also has water but it's in solid state and the temperature also is good, not during the nights but still is good enough.

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Read 2 more answers
Calculate the percentage increase in speed of the cyclist when the power output changes from 200 W to 300 W.
Rom4ik [11]

Answer:

<em>50%</em>

Explanation:

Given

Initial power = 200W

Final power = 300W

Increment = 300 - 200 = 100W

percentage increase = increment/initial power * 100

percentage increase = 100/200 * 100%

percentage increase = 0.5 * 100

percentage increase = 50%

<em>Hence the percentage increase in speed is 50%</em>

6 0
2 years ago
The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 2.0 rev/s in 10.0 s. At th
Arte-miy333 [17]

Answer:

22 revolutions

Explanation:

2 rev/s = 2*(2π rad/rev) = 12.57 rad/s

The angular acceleration when it starting

\alpha_a = \frac{\Delta \omega}{\Delta t} = \frac{12.57}{10} = 1.257 rad/s^2

The angular acceleration when it stopping:

\alpha_o = \frac{\Delta \omega}{\Delta t} = \frac{-12.57}{12} = -1.05 rad/s^2

The angular distance it covers when starting from rest:

\omega^2 - 0^2 = 2\alpha_a\theta_a

\theta_a = \frac{\omega^2}{2\alpha_a} = \frac{12.57^2}{2*1.257} = 62.8 rad

The angular distance it covers when coming to complete stop:

0 - \omega^2 = 2\alpha_o\theta_o

\theta_o = \frac{-\omega^2}{2\alpha_o} = \frac{-12.57^2}{2*(-1.05)} = 75.4 rad

So the total angular distance it covers within 22 s is 62.8 + 75.4 = 138.23 rad or 138.23 / (2π) = 22 revolutions

6 0
3 years ago
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