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3 years ago

In every balanced chemical equation,each side of the equation has the same number of?

1 answer:

4 0

In every balanced chemical equation, each side of the equation has the same number of <u>atoms</u> of reactants and products.

For example, let's take this chemical equation.

This is the chemical equation for carbon monoxide reacting with dihydrogen to form octane and water.

8 CO + 17 H2 → C8H18 + 8 H2O

On this side, we have 8 carbon monoxide atoms and 34 dihydrogen atoms.

On the other side, we have 8 carbon atoms and 18 hydrogen atoms + 16 hydrogen atoms.

Therefore, even though the coefficients are different there is still an equal number of atoms on each side.

8 Carbon Monoxide , 34 Dihydrogen = 8 Carbon Monoxide + 34 Dihydrogen

You might be interested in

What happens to the concentration of the reactants and products during the course of a forward chemical reaction

chubhunter [2.5K]

Hello!

The concentration of the reactants decreases and the concentration of products increases during the course of a forward chemical reaction.

A chemical reaction is a thermodynamical process in which two or more substances (called reagents) undergo transformation by the breaking and rearrangement of their chemical bonds to form another substance(s), called products. In a forward chemical reaction, the reagents are being consumed, so their concentration will decrease, increasing the concentration of products as they are the result of the reaction.

The study of how concentration changes with time in a chemical reaction is called reaction kinetics.

Have a nice day!

3 0

3 years ago

KBr (aq) + AgNO3 (aq) → KNO3 (aq) + AgBr (s)

Mnenie [13.5K]

<h3>Answer:</h3>

B Aqueous

<h3>Explanation:</h3>

We are given the equation;

KBr (aq) + AgNO₃ (aq) → KNO₃ (aq) + AgBr (s)

The equation shows a precipitation reaction or a double displacement reaction.
Precipitation reaction because two soluble salts reacts to produce a precipitate as one of the product.
Double displacement reaction because the salts exchange cations and anions to form new compounds
In the equation;
KBr is in aqueous state since all salts of potassium (K) are soluble in water.
KNO₃ and AgNO₃ are also in aqueous state as all nitrates are soluble in water.
AgBr on the other hand is in solid state since its a precipitate that is insoluble in water.

8 0

3 years ago

A rigid tank contains 0.66 mol of oxygen (O2). Find the mass of oxygen that must be withdrawn from the tank to lower the pressur

dsp73

Answer:

12.8 g of $O_{2}$ must be withdrawn from tank

Explanation:

Let's assume $O_{2}$ gas inside tank behaves ideally.

According to ideal gas equation- $PV=nRT$

where P is pressure of $O_{2}$ , V is volume of $O_{2}$ , n is number of moles of $O_{2}$ , R is gas constant and T is temperature in kelvin scale.

We can also write, $\frac{V}{RT}=\frac{n}{P}$

Here V, T and R are constants.

So, $\frac{n}{P}$ ratio will also be constant before and after removal of $O_{2}$ from tank

Hence, $\frac{n_{before}}{P_{before}}=\frac{n_{after}}{P_{after}}$

Here, $\frac{n_{before}}{P_{before}}=\frac{0.66mol}{43atm}$ and $P_{after}=17atm$

So, $n_{after}=\frac{n_{before}}{P_{before}}\times P_{after}=\frac{0.66mol}{43atm}\times 17atm=0.26mol$

So, moles of $O_{2}$ must be withdrawn = (0.66 - 0.26) mol = 0.40 mol

Molar mass of $O_{2}$ = 32 g/mol

So, mass of $O_{2}$ must be withdrawn = $(32\times 0.40)g=12.8g$

7 0

3 years ago

What mass of oxygen reacts when 84.9 g of iron is consumed in the following reaction: Fe+O2= Fe2O3

konstantin123 [22]

First we will calculate the number of moles of Iron:
$n = \frac{m}{M}
$ , where n is the number of moles, m is the mass of iron in the reaction and M is the Atomic weight.
$n= \frac{84.9}{55.845} = 1,52$ moles of Iron.
The same number of moles of Oxygen will take part in the reaction.
So $1,52= \frac{mOxygen}{32}$ where 32 is the Atomical Weight of Oxygen (16 x 2).
=> $mOxygen=32*1,52=48,64$ g

6 0

3 years ago

Read 2 more answers

A solid mixture consists of 47.6g of KNO3 (potassium nitrate) and 8.4g of K2SO4 (potassium sulfate). The mixture is added to 130

IgorLugansk [536]

<u>Answer:</u> No crystals of potassium sulfate will be seen at 0°C for the given amount.

<u>Explanation:</u>

We are given:

Mass of potassium nitrate = 47.6 g

Mass of potassium sulfate = 8.4 g

Mass of water = 130. g

Solubility of potassium sulfate in water at 0°C = 7.4 g/100 g

This means that 7.4 grams of potassium sulfate is soluble in 100 grams of water

Applying unitary method:

In 100 grams of water, the amount of potassium sulfate dissolved is 7.4 grams

So, in 130 grams of water, the amount of potassium sulfate dissolved will be $\frac{7.4}{100}\times 130=9.62g$

As, the soluble amount is greater than the given amount of potassium sulfate

This means that, all of potassium sulfate will be dissolved.

Hence, no crystals of potassium sulfate will be seen at 0°C for the given amount.

7 0

3 years ago