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harina [27]
3 years ago
9

What kind of small objects composes much of the universe

Chemistry
1 answer:
Ivanshal [37]3 years ago
7 0
I believe it would be A) atoms because atoms are pretty much the smallest unit of matter.......hope it helps:)
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Which agent causes sand dunes to form?
Sunny_sXe [5.5K]
The wind carrying the wind will Crete sand dunes
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4 years ago
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Describe the quantum model of an atom in terms of energy levels, sublevels, and orbitals. (Any atom is acceptable)
irakobra [83]
<span>Quantum mechanic model is based on mathematics. As per this theory the exact position and momentum of electron is impossible to understand. It uses complex shapes of orbitals called electron clouds. n describes the energy of an electron. Larger the value of n larger the distance of electron from the nucleus and larger the orbital. l describles the shape of orbital. Orbitals having same of value of n and different values for l are called subshells.</span>
5 0
3 years ago
The filling of which orbital is represented by the transition metals in period 4?
Sindrei [870]

Answer: 3d

Explantion:

1) Period 4 contains the elements with atomic numbers 19 through 36.

2) The elements with atomic numbers 19 (K) and 20 (Ca) fill the orbital 4s.

3) After that, as Aufbau's rule may help you to remember, the energy of the orbitals 3d is lower than the energy of the orbtitals 4p. So, the element 21 (Sc) start fillind the orbital 3d.

There are ten 3d orbitals, so the elements 21 through 30 fill the 3d orbitals.

Those elements, called transition metals are: Sc, Ti, V, Cr, Mn, Fe, Co, Ni, Cu, and Zn.

When the 3d orbitals are full, the next elements in the same period 4, fill the six 4p orbitals.

3 0
3 years ago
Read 2 more answers
What is ΔG° at 298 K for the following equilibrium? Ag+(aq) + 2NH3(aq) Ag(NH3)2+(aq); Kf = 1.7 × 107 at 298 K a. 41 kJ b. 0 c. –
jekas [21]

Answer:

ΔG° = 41.248 KJ/mol (298 K); the correct answer is a) 41 KJ

Explanation:

Ag+(aq)  +  2NH3(aq)  ↔ Ag(NH3)2+(aq)

⇒ Kf = 1.7 E7; T =298K  

⇒ ΔG° = - RT Ln Kf.....for aqueous solutions

∴ R = 8.314 J/mol.K

⇒ ΔG° = - ( 8.314 J/mol.K ) * ( 278 K ) ln ( 1.7 E7 )

⇒ ΔG° = 41248.41 J/mol * ( KJ / 1000J )

⇒ ΔG° = 41.248 KJ/mol

7 0
3 years ago
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Calculate the specific heat capacity of a piece of ice if 1.30 kg of the wood absorbs 6.75×104 joules of heat, and its temperatu
Gre4nikov [31]

Answer:

c=2.0769\  \frac{J}{g\ \textdegree C}

Explanation:

-Specific heat capacity is given by the formula:

q=mc\bigtriangleup T

Where:

q is the heat gained or loosed by the substance

m is the mass of the substance

c is the specific heat of the substance

\bigtriangleup T is the change in temperature

#We make c the subject of the formula and substitute to solve for it:

q=mc\bigtriangleup T\\\\c=\frac{q}{m\bigtriangleup T}\\\\\bigtriangleup T=(57-32)\textdegree C=25\textdegree C\\\\\therefore c=\frac{6.75\times 10^4J}{1.3\times 1000\ g\times 25\textdegree  C}\\\\=2.0769 \ \frac{J}{g\ \textdegree C}

Hence, the specific heat capacity of the ice is 2.0769 \frac{J}{g\ \textdegree C}

8 0
3 years ago
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