All categories

3 years ago

Aplicaciones del agua pesada en medicina

Chemistry

2 answers:

ELEN [110]3 years ago

7 0

Answer:

tecnológico, ya que funciona como moderador y regulador en los reactores de uranio natural en los procesos de fisión nuclear. El empleo del agua pesada en este caso permite que una central nuclear pueda generar energía eléctrica. habituales. como en laboratorios y centros de investigación.

Phantasy [73]3 years ago

6 0

Answer:

What single percentage change is equivalent to a 11% increase followed by a 15% increase?

Explanation:

What single percentage change is equivalent to a 11% increase followed by a 15% increase?

You might be interested in

Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.89×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.25×10−4, what is the

Sergio [31]

Answer:

$1.2\times 10^{-2}$

Explanation:

The given reactions are:

PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq) $K_3 = 1.89\times 10^{-10}$

AgCl(aq)⇌Ag+(aq)+Cl−(aq) $K_4 = 1.25\times 10^{-4}$

Required reaction is:

PbCl2(aq)+2Ag+(aq)⇌2AgCl(aq)+Pb2+(aq)

$K_f = \frac{K_3}{K_4^2}\\=\frac{1.89\times 10^{-10}}{1.25\times 10^{-4}}^2\\=1.2\times 10^{-2}$

4 0

3 years ago

Sodium is a compound O True or O False

MA_775_DIABLO [31]

Answer:

i think false.

Explanation:

tell me if this is wrong

6 0

3 years ago

Read 2 more answers

Which type of radiation is the main hazard during radiological procedures

Alla [95]

The main hazard is the Radiation and the Gamma rays that are dispersed

3 0

3 years ago

The kinetic theory assumes that collisions of gas particles are perfectly elastic. What does this statement mean?

In-s [12.5K]

Stating that collisions of gas particles are perfectly elastic means that no kinetic energy is lost when the gases collide, and no kinetic energy is gained. Some of the properties of gases include volume, pressure, thermal conductivity, pressure, and viscosity.

5 0

3 years ago

Read 2 more answers

Homes in rural areas where natural gas service is not available often rely on propane to fuel kitchen ranges. The propane is sto

Neporo4naja [7]

Answer:

2666.7 hours

Explanation:

The key to solve this problem is that we are given the propane gas consumed in one hour by giving us the information of the volume consumed at 1 atm, 298 K (25 +273). Using the gas law we can calculate the rate of consumption of propane per hour, and from here we can calculate its mass and converting it to gallons and finally diving the 400 gallos by this number.

PV = nRT ∴ n = PV/RT

n = 1 atm x 165 L/ (0.08206 Latm/kmol x 298 K ) = 6.75 mol propane

Mass propane :

6.75 mol x 44 g/mol = 296.88 g

convert this to Kg:

296.88 g/ 1000 g/Kg = 0.30 Kg

calculate the volume in liters this represents by dividing by the density:

0.30 Kg / 0.5077 Kg/L = 0.59 L

changing this to gallons

0.59 L x 1 gallon/3.785 L = 0.15 gallon

and finally calculate how many hours the 400 gallons propane tank will deliver

400 gallon/ 0.15 gallon/hr = 2666.7 hr

6 0

3 years ago