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2 years ago

8

Aplicaciones del agua pesada en medicina

2 answers:

ELEN [110]2 years ago

7 0

Answer:

tecnológico, ya que funciona como moderador y regulador en los reactores de uranio natural en los procesos de fisión nuclear. El empleo del agua pesada en este caso permite que una central nuclear pueda generar energía eléctrica. habituales. como en laboratorios y centros de investigación.

Phantasy [73]2 years ago

6 0

Answer:

What single percentage change is equivalent to a 11% increase followed by a 15% increase?

Explanation:

What single percentage change is equivalent to a 11% increase followed by a 15% increase?

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Unknown element x is a metal that ionically bonds to sulfur.is the formula, x3s feasible? why or why not?a)it is feasible. the t

nasty-shy [4]

The correct answer is:
d) No, it is not feasible. three metallic ions cannot provide the exact number of electrons that one sulfur needs for the ionic bond.
Because Sulfur is divalent so it need to gain 2 electrons from metal so if we have 3 metals they can't provide only two electrons only.

8 0

3 years ago

Read 2 more answers

How many particles would be found in a 1.224 g sample of K2O

lbvjy [14]

Answer:

9.96*10^21

Explanation:

Molar mass of K2O=29*2+16

= 74g per mol

number of moles in the sample= 1.224/ 74

=0.1654

Number of particles in 1 mole=6.0221409*10^23

Number of particles= 0.01654*6.0221409*10^23

=9.96*10^21

4 0

3 years ago

Read 2 more answers

If an object is moving right at 10 N and a force is applied from the left at 8N, what is the net force on the object?

ryzh [129]

Answer:

If an object is moving at a constant speed in a constant rightward direction, then the acceleration is zero and the net force must be zero.

5 0

2 years ago

A transfer of heat within a liquid or gas that involves warm particles moving in currents is?

myrzilka [38]

It is called convection. When warm air, or current, moves up and disperse outwards as cold air, or current, moves into the warmer region.

3 0

3 years ago

Read 2 more answers

Titanium has an HCP crystal structure, a c/a ratio of 1.669, an atomic weight of 47.87 g/mol, and a density of 4.51 g/cm3. Compu

IrinaK [193]

Answer : The atomic radius for Ti is, $1.45\times 10^{-8}cm$

Explanation :

Atomic weight = 47.87 g/mole

Avogadro's number $(N_{A})=6.022\times 10^{23} mol^{-1}$

First we have to calculate the volume of HCP crystal structure.

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times V}$ .............(1)

where,

$\rho$ = density = $4.51g/cm^3$

Z = number of atom in unit cell (for HCP = 6)

M = atomic mass = 47.87 g/mole

$(N_{A})$ = Avogadro's number

V = volume of HCP crystal structure = ?

Now put all the values in above formula (1), we get

$4.51g/cm^3=\frac{6\times (47.87g/mol)}{(6.022\times 10^{23}mol^{-1}) \times V}$

$V=1.06\times 10^{-22}cm^3$

Now we have to calculate the atomic radius for Ti.

Formula used :

$V=6R^2c\sqrt{3}$

Given:

c/a ratio = 1.669 that means, c = 1.669 a

Now put (c = 1.669 a) and (a = 2R) in this formula, we get:

$V=6R^2\times (1.669a)\sqrt{3}$

$V=6R^2\times (1.669\times 2R)\sqrt{3}$

$V=(1.669)\times (12\sqrt{3})R^3$

Now put all the given values in this formula, we get:

$1.06\times 10^{-22}cm^3=(1.669)\times (12\sqrt{3})R^3$

$R=1.45\times 10^{-8}cm$

Therefore, the atomic radius for Ti is, $1.45\times 10^{-8}cm$

3 0

3 years ago