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ad-work [718]
3 years ago
8

Aplicaciones del agua pesada en medicina

Chemistry
2 answers:
ELEN [110]3 years ago
7 0

Answer:

tecnológico, ya que funciona como moderador y regulador en los reactores de uranio natural en los procesos de fisión nuclear. El empleo del agua pesada en este caso permite que una central nuclear pueda generar energía eléctrica. habituales. como en laboratorios y centros de investigación.

Phantasy [73]3 years ago
6 0

Answer:

What single percentage change is equivalent to a 11% increase followed by a 15% increase?

Explanation:

What single percentage change is equivalent to a 11% increase followed by a 15% increase?

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What would be considered the reactant(s) in H2 + O2 <-> H2O
jeka94

Answer:

H2+ 02

Explanation:

becuase those 2 are at the beginning of the equation and in front of the equilibrium sign :)

6 0
4 years ago
A laboratory bottle of helium gas occupies a volume of 2.0 L at 760 mm Hg. Calculate the new pressure if the
Fantom [35]

Answer:

<h2>844.4 mmHg</h2>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

From the question we have

P_2 =  \frac{2 \times 760}{1.8}  =  \frac{1520}{1.8}  \\ =  844.4444...

We have the final answer as

<h3>844.4 mmHg</h3>

Hope this helps you

8 0
3 years ago
As electrical energy is converted into heat energy, the total amount in the system
Aleks04 [339]
<span>c. remains the same
</span>----------------------------------------------------
As electrical energy is converted into heat energy, the total amount in the system remains the same
--------------
according to law of conservation of energy
3 0
4 years ago
Read 2 more answers
Consider the equilibrium
vladimir1956 [14]

Answer:

Kp^{1000K}=0.141\\Kp^{298.15K}=2.01x10^{-18}

\Delta _rG=1.01x10^5J/mol

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

C_2H_6(g)\rightleftharpoons H_2(g)+C_2H_4(g)

Thus, Kp for this reaction is computed based on the given molar fractions and the total pressure at equilibrium, as shown below:

p_{C_2H_6}^{EQ}=2bar*0.592=1.184bar\\p_{C_2H_4}^{EQ}=2bar*0.204=0.408bar\\p_{H_2}^{EQ}=2bar*0.204=0.408bar

Kp=\frac{p_{C_2H_4}^{EQ}p_{H_2}^{EQ}}{p_{C_2H_6}^{EQ}}=\frac{(0.408)(0.408)}{1.184}=0.141

Now, by using the Van't Hoff equation one computes the equilibrium constant at 298.15K assuming the enthalpy of reaction remains constant:

Ln(Kp^{298.15K})=Ln(Kp^{1000K})-\frac{\Delta _rH}{R}*(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=Ln(0.141)-\frac{137000J/mol}{8.314J/mol*K} *(\frac{1}{298.15K}-\frac{1}{1000K} )\\\\Ln(Kp^{298.15K})=-40.749\\\\Kp^{298.15K}=exp(-40.749)=2.01x10^{-18}

Finally, the Gibbs free energy for the reaction at 298.15K is:

\Delta _rG=-RTln(Kp^{298.15K})=8.314J/mol*K*298.15K*ln(2.01x10^{-18})\\\Delta _rG=1.01x10^5J/mol

Best regards.

3 0
4 years ago
For which compound is the process of dissolving in water exothermic?
Leokris [45]

Answer: Option (2) is the correct answer.

Explanation:

A chemical reaction in which reactants absorb energy is known as an endothermic reaction. Also, in this reaction energy of reactants is less than the energy of products.

For example, when ammonium chloride is dissolved in water then the solution becomes cold as the reaction is endothermic in nature.

Whereas a chemical reaction in which energy is released is known as exothermic reaction. Also, in this type of reactions energy of reactants is more than the energy of products.

For example, when NaOH is dissolve in water then heat is released as it dissociates into sodium and hydroxide ions. Further, product formed that is, species sodium and hydroxide ions acquire low energy state. Hence, the reaction is exothermic in nature.

Thus, we can conclude that NaOH is the compound in which process of dissolving in water is exothermic.

8 0
3 years ago
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