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ioda
3 years ago
13

Write the formula for the conjugate base for the following acids. Thank you ​

Chemistry
2 answers:
Llana [10]3 years ago
7 0

Answer:

See the answer and explanation below , please.

Explanation:

A conjugate base is defined as that formed after an acid donates its proton.

For each article, a continuation of the conjugate bases (highlighted in bold), for dissociation in water:

a) HF + H20 --> F- + H30+      

b) H20+ H20 --> OH-  + H30+

C)H2PO3-  + H20--> HPO3 2-   + H30+

d) HSO4- + H20 -->  SO4 2- + H30+

E) HCL02 + H20 --> CLO02 -   + H30+

Snezhnost [94]3 years ago
6 0

Answer:

a. HF =  F-

b. H2O = H3O+(hydronium ion)

c. H2po3- =HPO3-2 ion

d. HSO4=SO4 (2-)

e. HCLO2= ClO2

Explanation:

The species that is formed is the acid's conjugate base. A more general definition is that a conjugate base is the base member, X-, of a pair of compounds that transform into each other by gaining or losing a proton. The conjugate base is able to gain or absorb a proton in a chemical reaction.

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What volume (mL) of the partially neutralized stomach acid was neutralized by NaOH during the titration? (portion of 25.00 mL sa
almond37 [142]

The question is incomplete, here is the complete question:

What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

<u>Answer:</u> The volume of HCl neutralized is 1.25 mL

<u>Explanation:</u>

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of stomach acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.1M\\V_2=25mL

Putting values in above equation, we get:

1\times 2\times V_1=1\times 0.1\times 25\\\\V_1=\frac{1\times 0.1\times 25}{1\times 2}=1.25mL

Hence, the volume of HCl neutralized is 1.25 mL

3 0
3 years ago
Plz help 10 points!!!!!!
Alex_Xolod [135]

Answer:

Where are all my chemistry geniuses at??

1. 2HG + O2 = 2HGO

2. Ca + 2H2O = Ca(OH)2 + H2

3. H2 + Cl2 = 2HCl

4. Fe + S = FeS

Explanation:

Hope it helped!

8 0
3 years ago
Read 2 more answers
What is the mass of a solution that has a density of 0.775 g/ml and a volume of 50.0ml?
Margarita [4]
Hey there!

D = m / V

0.775 = m / 50.0

m = 0.775 * 50.0

m = 38.75 g
6 0
3 years ago
Rate law equation The rate of a chemical reaction depends on the concentrations of the reactants. For the general reaction betwe
jekas [21]

<u>Answer:</u> The reaction order with respect to A is 'm'

<u>Explanation:</u>

Order of the reaction is the sum of the concentration of terms on which the rate of the reaction actually depends. It is equal to the sum of the exponents of the molar concentration in the rate law expression.

Elementary reactions the reactions for which the order of the reaction is same as its molecularity and order with respect to each reactant is equal to its stoichiometric coefficient as represented in the balanced chemical equation.

The given chemical equation follows:

aA+bB\rightleftharpoons cC+dD

The rate of the above reaction is given to us as:

Rate=k[A]^m[B]^n

In the above rate law expression, the order with respect to the reactants is not equal to the stoichiometric coefficients. Thus, it is not an elementary reaction.

Order with respect to reactant A = m

Order with respect to reactant B = n

Hence, the reaction order with respect to A is 'm'

8 0
3 years ago
How many molecules make up 8.41 moles of Ca2(SO3)?
sammy [17]

Answer:

<h3>5.06282 × 10²⁴ molecules</h3>

Explanation:

The number of molecules of Ca2(SO3) can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 8.41 × 6.02 × 10²³

We have the final answer as

<h3>5.06282 × 10²⁴ molecules</h3>

Hope this helps you

3 0
2 years ago
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