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3 years ago

What is the direction of the magnetic field b⃗ net at point a? Recall that the currents in the two wires have equal magnitudes.

Physics

1 answer:

andrew11 [14]3 years ago

6 0

Answer:

Explanation:

The direction of a magnetic field indicates where the magnetic inluence on the electric charges are directed to.

From the given question, we are to determine the direction of the magnetic field bnet at a point A.

Also, having the notion that the currents in the two wires have equal magnitudes, Then:

$\bar{B_{net}} = \bar{B_1} + \bar{B_2}$

$\bar{B_{net}} = \frac{\mu_oI}{2 \pi r } \bar {k}+ \frac{\mu_oI}{2 \pi r } \bar {k}$

$\bar{B_{net}} = \frac{2 \mu_oI}{2 \pi r } \bar {k} \ out$

Thus; $\bar{B_{net}}$ points out of the screen at A.

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A net downward force of 20 N causes a book to fall towards the ground at m/s2. What is the book’s mass? Consider air resistance

stira [4]

If we have to figure air resistance into it, then we don't have enough information to find an answer.

If the air around it is going to have an effect on how it falls, then it'll depend on the thickness of the book, the shape of the book, whether it's a hard-cover or soft-cover, how far the covers stick out past the pages, how smooth or rough the covers are, how bumpy the binding it. and what position you hold it in before you let it go.

(THAT's why we always ignore air resistance, especially when the question is actually about gravity anyway.)

4 0

3 years ago

A block with mass of 10 kg is on a frictionless surface. One hand on the left side of the block is pushing it to the right. A se

igomit [66]

Answer:

$W_2=-12J$

Explanation:

The work of force 2 will be given by the vectorial equation $W_2=F_2.d$ . We know the value of $F_1$ and have information about its movement, which relates to the net force $F=F_1+F_2$ .

About this movement we can obtain the acceleration using the equation $v_f^2=v_i^2+2ad$ . Since it departs from rest we have $a=\frac{v_f^2}{2d}$ .

And then using Newton's 2dn Law we can obtain the net force F=ma, thus we will have $F_2=F-F_1=ma-F1=\frac{mv_f^2}{2d}-F_1$

And we had the work done by force 2 as:

$W_2=F_2.d=\frac{mv_f^2}{2}-F_1d$

(The sign will be given algebraically since we take positive the direction to the right.)

With our values:

$W_2=\frac{(10kg)(2m/s)^2}{2}-(8N)(4m)=-12J$

Another (shorter but maybe less intuitive way for someone who is learning) way of doing this would have been to say that the work done by both forces would be equal to the variation of kinetic energy:

$W_1+W_2=K_f-K_i=K_f=\frac{mv_f^2}{2}$

Which leads us to the previous equation straightforwardly.

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3 years ago

Why meter cube is called derived unit

gregori [183]

Answer:

Because it is the result of two more fundamental units, a derived unit is termed that. For volume, the cubic meter (m³) is the fundamental unit of area. Any number that cannot be measured directly with any equipment is referred to as a derived unit. For example, we can't quantify a substance's density using a rule, scale, or bucket.

OAmalOHopeO

7 0

3 years ago

Read 2 more answers

Manuel is holding a 5kg box. How much force is the box exerting on him?In what direction

soldi70 [24.7K]

The force the box is exerting on Manuel is the weight of the box, downward:
$W=mg=(5 kg)(9.81 m/s^2)=49.05 N$
and this force is perfectly balanced by the constraint reaction applied by Manuel's hand, pushing upward.

3 0

4 years ago

Calculating work for different springs Calculate the work required to stretch the following springs 0.5 m from their equilibrium

Rina8888 [55]

Answer:

Part a)

U = 31.25 J

Part b)

U = 312.5 J

Explanation:

Part A)

A spring that requires a force of 50 N to be stretched 0.2 m from its equilibrium position.