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xxTIMURxx [149]
3 years ago
6

I really need help with this question someone plz help !

Physics
1 answer:
Vika [28.1K]3 years ago
7 0

Answer:

The answer is option 2.

Explanation:

Both sides are pulling the rope with equal force where the rope doesn't move. So they have a <u>b</u><u>a</u><u>l</u><u>a</u><u>n</u><u>c</u><u>e</u><u>d</u><u> </u><u>f</u><u>o</u><u>r</u><u>c</u><u>e</u><u>s</u>.

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To view an interactive solution to a problem that is similar to this one, select Interactive Solution 7.24. A 0.0146-kg bullet i
Vinil7 [7]

Answer:

0.25223 seconds.

Explanation:

m_1 = Mass of bullet = 0.0146 kg

m_2 = Mass of block = 2.55 kg

v = Combined velocity

u_1 = Velocity of bullet = 816 m/s

g = Acceleration due to gravity = 9.81 m/s²

As linear momentum is conserved

m_1u_1 + m_2u_2 =(m_1 + m_2)v

Now u_2=v as the block (with the bullet in it) reverses direction and rises,

m_1u_1 + m_2v =(m_1 + m_2)v\\\Rightarrow m_1u_1=(m_1 + m_2)v-m_2v\\\Rightarrow 0.0146\times 816=(0.0146 + 2.55)v-(-2.55v)\\\Rightarrow 11.9136=2.2646v+2.55v\\\Rightarrow 11.9136=4.8146v\\\Rightarrow v=\frac{11.9136}{4.8146}\\\Rightarrow v=2.47447\ m/s

Equation of motion

v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{2.47447-0}{9.81}\\\Rightarrow t=0.25223\ s

The time t is 0.25223 seconds.

3 0
3 years ago
Suppose you have a car with a battery that applies 12.5 V to the starter.
Marat540 [252]

Answer:

R = 0.1 ohms

Explanation:

It is given that,

Voltage of the battery, V = 12.5 V

Current flowing in the car's starter, I = 125 A

We need to find the effective resistance of a car's starter. It can be calculated using Ohm's law. Let R is the resistance.

V=IR\\\\R=\dfrac{V}{I}\\\\R=\dfrac{12.5}{125}\\\\R=0.1\ \Omega

So, the resistance of the car's starter is 0.1 ohms.

7 0
3 years ago
If a machine has an efficiency of 50% and an input of 3 J, what is the output?
uranmaximum [27]

Answer:

150J

Explanation:

work output/work input=100%

so just make work output the subject

6 0
3 years ago
A spaceship travels toward the Earth at a speed of 0.97c. The occupants of the ship are standing with their torsos parallel to t
Ket [755]

Answer:

Explanation:

We shall apply length contraction einstein's relativistic formula to calculate the length observed by observer on the earth . For the observer , increased length will be observed for an observer on the earth

L=\frac{.5}{\sqrt{1-(\frac{.97c}{c})^2 } }

L=\frac{.5}{.24}

L= 2.05

The length will appear to be 2.05 m . and width will appear to be .5 m  to the observer on the spaceship. . It is so because it is length which is moving parallel to the direction of travel. Width will remain unchanged.  

3 0
4 years ago
What compound is formed from a tight network of oppositely charged ions
Vsevolod [243]

Answer:

salt

Explanation:

7 0
3 years ago
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