1. clavicle = collarbone
2. vertebrae = backbone
3. scapula = shoulder blade
4. femur = thigh
5. humerus = upper arm
6. patella = kneecap
7. cranium = skull
8. tibia = lower leg
9. radius/ulna = forearm
10. phalanges = fingers/toes
Explanation:
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Answer:
The acceleration of the collar is 10 m/s²
Explanation:
Given;
mass of the collar, m = 1 kg
applied force on the bar, F = 10 N
The acceleration of the collar can be calculated by applying Newton's second law of motion;
F = ma
where;
F is the applied force
m is mass of the object
a is the acceleration
a = F / m
a = 10 / 1
a = 10 m/s²
Therefore, the acceleration of the collar is 10 m/s²
Answer:


Explanation:
Given Data:
Numbers of times Telescope cycled around the earth in 6 years=37,000 times
Total Distance traveled in 6 years by the Hubble Space Telescope=1,280,000,000 Km
Find:
Kilometers in one Orbit=?
Solution:
Kilometers in 37,000 Orbits=1,280,000,000 Km
Kilometers in 1 Orbit=1,280,000,000/37,000
In Scientific Notation:


Kilometers in 1 Orbit=34594.594 Km
Kilometers in 1 Orbit in Scientific notation:

Answer:
Explanation:
Given that,.
A house hold power consumption is
475 KWh
Gas used is
135 thermal gas for month
Given that, 1 thermal = 29.3 KWh
Then,
135 thermal = 135 × 29.3 = 3955.5 KWh
So, total power used is
P = 475 + 3955.5
P =4430.5 KWh
Since 1 hr = 3600 seconds
So, the energy consumed for 1hr is
1KW = 1000W
P = energy / time
Energy = Power × time
E = 4430.5 KWhr × 1000W / KW × 3600s / hr
E = 1.595 × 10^10 J
So, using Albert Einstein relativity equation
E = mc²
m = E / c²
c is speed of light = 3 × 10^8 m/s
m = 1.595 × 10^10 / (3 × 10^8)²
m = 1.77 × 10^-7 kg
Then,
1 kg = 10^6 mg
m = 1.77 × 10^-7 kg × 10^6 mg / kg
m = 0.177mg
m ≈ 0.18 mg