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Setler79 [48]
3 years ago
5

Provide three specific examples of how this cloning is used.

Chemistry
1 answer:
lara [203]3 years ago
5 0

Answer:

Cloning is used to duplicate different organisms

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marysya [2.9K]

Answer:

Hi, even though this is really not a question or an answer to a question.

Explanation:

Do you know if any of this stuff involves 6th grade?

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4 years ago
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Cobalt chloride Select one: a. Does not exist as a hydrate b. Forms a single hydrate which may be pink or blue c. Forms differen
Anarel [89]

Answer:

c. Forms different hydrates which have different colors

Explanation:

4 0
3 years ago
La aspirina se prepara haciendo reaccionar ácido salicílico con exceso de anhídrido etanoico. En un experimento, 50.05 g de ácid
Tanya [424]

La aspirina se prepara haciendo reaccionar ácido salicílico con exceso de anhídrido etanoico. En un experimento, 50.05 g de ácido salicílico se convirtieron en 55.45 g de aspirina. ¿Cuál fue el porcentaje de rendimiento?

<em>In English:</em>

Aspirin is prepared by reacting salicylic acid with excess ethanoic anhydride. In one experiment, 50.05 g of salicylic acid was converted to 55.45 g of aspirin. What was the yield percentage?

Answer:

el rendimiento porcentual para la cantidad dada de ácido salicílico es 84.99 %

<em>In English:</em>

<em>the percent yield for the given amount of salicylic acid is </em><em>84.99%</em>

<em></em>

Explanation:

La ecuación química equilibrada para la reacción se puede escribir como:

C₇H₆O₃ + C₄H₆O₃    →    C₉H₈O₄ + HC₂H₃O₂

Para la reacción mostrada arriba; El reactivo limitante de la reacción es el ácido salicílico. Ahora; calcular el porcentaje de rendimiento; se espera que primero determinemos el rendimiento teórico de la reacción.

Entonces; la fórmula para calcular el porcentaje de rendimiento: \mathbf {= \frac{actual \ yield }{theoretical \ yield } *100 }  

El rendimiento teórico se determina de la siguiente manera:

50.05 g * 1 mol / 138.21 g / mol de C₇H₆O₃ * 1 mol de C₉H₈O₄ / 1 mol de C₇H₆O₃ * 180.157 g / mol de C₉H₈O₄ = 65.24 g de C₉H₈O₄

Porcentaje de rendimiento \mathbf {= \frac{55.45 }{65.24 } *100 }

Porcentaje de rendimiento = 84.99%

Por lo tanto, el porcentaje de rendimiento para la cantidad dada de ácido salicílico es 84.99%

<em>In English:</em>

<em>The balanced chemical eqaution for the reaction can be written as:</em>

<em>C₇H₆O₃ + C₄H₆O₃    →    C₉H₈O₄ + HC₂H₃O₂</em>

<em>For the reaction shown above;  The limiting reactant from the reaction is  salicylic acid. Now; to calculate the percentage yield ; we are expected to first determine the theoretical yield of the reaction. </em>

<em>So; the formula for calculating the percentage yield </em>\mathbf {= \frac{actual \ yield }{theoretical \ yield } *100 }<em>  </em>

<em />

<em>The theoretical yield is determined as follows:</em>

<em>50.05 g * 1 mol/ 138.21 g/mol of C₇H₆O₃ * 1 mol of C₉H₈O₄/ 1 mol of C₇H₆O₃ * 180.157 g/mol of C₉H₈O₄ = 65.24 g of C₉H₈O₄ is produced</em>

<em />

<em>Percentage yield </em>\mathbf {= \frac{55.45 }{65.24 } *100 }<em />

<em>Percentage yield = 84.99%</em>

<em />

<em>Thus, the percent yield for the given amount of salicylic acid is </em><em>84.99%</em>

7 0
4 years ago
Sodium electron configuration in longhand notation
Elden [556K]

Answer:

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

Explanation:

Sodium is present in group 1.

It is alkali metal.

It has one valence electron.

The atomic number of sodium is 11.

Its atomic mass is 23 amu.

The longhand notation of electronic configuration of sodium can be written as,

Na₁₁ = 1s² 2s² 2p⁶ 3s¹

The electronic configuration in shorthand notation( noble gas) would be written as,

Na₁₁ = [Ne] 3s¹

Sodium loses its one valence electron to complete the octet and get stable thus form +1 cation.

It react with halogen and form salt. Such as sodium chloride.

2Na + Cl₂  →  2NaCl

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3 years ago
Why does a microscope stage have a small hole in it?
jarptica [38.1K]
Answer: B. Allow light to pass through. :)
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