Answer:
6.98%
Explanation:
% error= |experimental value - actual value|/actual value × 100
Experimental value= 4.6 cm
Actual value= 4.3 cm
% error = |4.6-4.3|/4.3 × 100
% error = 6.98%
The methane molecule in the stratosphere has a higher potential energy than the CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule.
The complete question is:
<em>For each of the following situations, you are asked which of two objects or substances has the higher energy. Explain your answer with reference to the capacity of each to do work and say whether the energy that distinguishes them is kinetic energy or potential energy.</em>
<em>a. (1) A methane molecule, CH4, in the stratosphere or (2) a CH3 molecule and a hydrogen atom formed from breaking one of the carbon-hydrogen bonds in a CH4 molecule.</em>
<h3>Which have a higher energy?</h3>
The methane molecule in the stratosphere is a stable molecule and possesses chemical potential energy.
The CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule are unstable molecules and possesses kinetic energy. However, some of their energy has been used in breaking the bond.
Thus, the methane molecule in the stratosphere has a higher potential energy than the CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule.
In conclusion, the energy in the methane molecule is higher.
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Answer:
melting
Explanation:
liquid is a good conductor of electricity
Answer:
Explanation:
98 gH
2
SO
4
contains1 mole of H
2
SO
4
.
1 mole of H
2
SO
4
contain=1 mole of sulphur atoms.
∴9.8 g of H
2
SO
4
contain =0.1 mol of sulphur atom.
Thus, number of sulphur-atoms =n×N
A
(in 9.8 g of H
2
SO
4
)
=0.1×6.023×10
23
=0.6023×10
23
.
The location of reduction in an electrochemical cell is called the anode.
An electrochemical cell ( galvanic cell ) is generate electric energy from chemical reactions. In galvanic cell species ( for example zinc and zinc cations ) from one half-cell lose electrons ( oxidation ) and species from other half-cell ( for example copper and copper cations ) gain electrons ( reduction ). Electric current is generated due to the flow of electrons from the anode that undergoes an oxidation reaction to the cathode which has a reduction reaction in the circuit of an outer wire circuit.
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