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bonufazy [111]
3 years ago
13

True or False? The shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is th

e circles radius

Mathematics
2 answers:
Ratling [72]3 years ago
6 0
Itis true <span>The shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is the circles radius</span>
ivolga24 [154]3 years ago
3 0

Answer:

True, This is circumcentre point of triangle.

Step-by-step explanation:

The shortest distance from the center of the circumscribed circle to the vertices of the inscribed triangle is the circles radius.

This is a circumcenter point of triangle whose distance from each vertex is same.

Circumcenter of triangle is a point of intersection of perpendicular bisector of the sides of triangle.

Please see the attachment.

If we draw a circle from a point circumcenter it will touches all three vertices of triangle.

The distance from centre of circle to point on circle is known as radius.

Thus, Statement is true.

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Area= 169(pie)mm(squared)<br><br> What's the radius and diameter
Natali [406]

You would have to divide by 3.14 to find the radius squared, and to find the diameter, just add the radius plus the radius.
4 0
3 years ago
Can I get help on this question or an example? I would really appreciate it.
gulaghasi [49]

Answer:

B = 0.95m + 29.95

Step-by-step explanation:

this is really y = mx + b

m is a rate, 0.95 per mile

b is the y-intercept, or the price you pay no matter what, 29.95

8 0
3 years ago
A right triangle has an area of 50 square inches. If the triangle is an isosceles triangle, what are the lengths of the legs of
Fed [463]
<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length.  Orient the base of this triangle so that it's horizontal, and represent its length by b.  Let h represent the height of the triangle.  Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.   

Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2.  Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).

The length of one of the legs is the sqrt of  [5sqrt(2)]^2+[5sqrt(2)]^2, or

sqrt(25(2)+25(2)) = sqrt(100) = 10.



</span>
4 0
3 years ago
What is the surface area of the cylinder shown below? Use 3.14 for π. A. 660 cm2 B. 863 cm2 C. 353.25 cm2 D. 785 cm2
lesantik [10]

Answer:

602.88cm²

Step-by-step explanation:

Find the image of the cylinder attached

Surface area of a cylinder = A=2πrh+2πr²

r is the radius = 4cm

Height h = 20cm

Substitute

A = 2πr(r+h)

A = 2π(4)(4+20)

A = 8π(24)

A = 192π

A = 192(3.14)

A = 602.88cm²

Hence the surface area of the cylinder is 602.88cm²

5 0
3 years ago
Danny worked 30 hours for $18.15/h. The following taxes were deducted from his gross pay: $50.31 in federal taxes, $36.17 in sta
Pavlova-9 [17]
I think the answer is b bc you do 18.15 * 30 then subtract all the taxes 

4 0
3 years ago
Read 2 more answers
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