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I am Lyosha [343]
3 years ago
8

Which word is the longest word in chemistry?​

Chemistry
1 answer:
Hunter-Best [27]3 years ago
4 0
Isoleucine' is the chemical name of 'titin' (also known as 'connectin') - the largest known protein. It has 189,819 letters.
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Helium decays to form lithium. Which equation correctly describes this decay? Superscript 6 Subscript 2 Baseline Upper H e right
Virty [35]

Answer:

Superscript 6 Subscript 2 Baseline Upper H e right arrow Superscript 6 Subscript 3 Baseline Upper L i + Superscript 0 Subscript negative 1 Baseline e

Explanation:

Helium decays by beta emission, in beta emission, the mass number of the parent and daughter nuclei are the same but the atomic number of the daughter nucleus increases by one hence it is found one place to the right of its parent in the periodic table.

Having said this, the decay of Helium to lithium may be written as follows;

6/2He -> 6/3Li + 0/-1e

4 0
3 years ago
Read 2 more answers
What is the atomic number of a sodium atom that has 11 protons and 12 neutrons?
galben [10]
Answer should be 23.
3 0
4 years ago
Which two organ systems work together to provide cells with oxygen and to remove carbon
-BARSIC- [3]

Answer:

Lungs

Explanation: The two organ systems that work together to provide the cells with oxygen and remove carbon dixoide from the body are the lungs.

3 0
3 years ago
Which statement describes a reason scientists predict that carbon dioxide emissions will increase over the next few decades? Cho
Ad libitum [116K]

Answer:

Many countries are undergoing an increase in technology and standard of living.

Explanation:

7 0
3 years ago
0.0200 M Fe3+ is initially mixed with 1.00 M oxalate ion, C2O42-, and they react according to the equation: Fe3+(aq) + 3 C2O42-(
Studentka2010 [4]

Answer : The concentration of Fe^{3+} at equilibrium is 0 M.

Solution :  Given,

Concentration of Fe^{3+} = 0.0200 M

Concentration of C_2O_4^{2-} = 1.00 M

The given equilibrium reaction is,

                            Fe^{3+}(aq)+3C_2O_4^{2-}(aq)\rightleftharpoons [Fe(C_2O_4)_3]^{3-}(aq)

Initially conc.       0.02         1.00                   0

At eqm.             (0.02-x)    (1.00-3x)                x

The expression of K_c will be,

K_c=\frac{[[Fe(C_2O_4)_3]^{3-}]}{[C_2O_4^{2-}]^3[Fe^{3+}]}

1.67\times 10^{20}=\frac{(x)^2}{(1.00-3x)^3\times (0.02-x)}

By solving the term, we get:

x=0.02M

Concentration of Fe^{3+} at equilibrium = 0.02 - x = 0.02 - 0.02 = 0 M

Therefore, the concentration of Fe^{3+} at equilibrium is 0 M.

4 0
3 years ago
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