Answer: A volume of 600 mL of 3.0 M 
solution can be prepared by using 100.0 mL OF 18 M .
Explanation:
Given: 
= ?, 
, 
Formula used to calculate the volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 600 mL of 3.0 M solution can be prepared by using 100.0 mL OF 18 M .
Sound increases my the sound waves
Answer:
K8S4O16 or K8(SO4)4 depending on if the SO4 is supposed to represent sulfate or not
Explanation:
Find the molar mass of K2SO4 first:
2K + S + 4O ≈ 174 g/mol
Divide the goal molar mass of 696 by the molar mass of the empirical formula:
696 / 174 = 4
This means you need to multiply everything in the empirical formula by 4:
K2SO4 --> K8S4O16 or K8(SO4)4 depending on if the SO4 is for sulfate or not
Answer: Option (c) is the correct answer.
Explanation:
A binary mixture is defined as the mixture which contains two components in the aqueous medium. The two components are solute and solvent.
And, volatility is defined as the ability of a liquid solution or substance to readily change into vapors.
For a binary solution the expression for relative volatility is as follows.
= 
where, 
= relative volatility of more volatile component i
= vapor-liquid equilibrium concentration of component i in the vapor phase
= vapor-liquid equilibrium concentration of component i in the liquid phase
= vapor-liquid equilibrium concentration of component j in the vapor phase
= vapor-liquid equilibrium concentration of component j in the liquid phase
So, when > 1 then separation by distillation is easier in nature.
Thus, we can conclude that in order to separate the components of a binary mixture, the relative volatility should be greater than unity.
They each have one valence electron in their outer shell, but they are also on the same row (period). If you follow this pattern, potassium will also have one valence electron.
Hope this helps!! :)
