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ziro4ka [17]
3 years ago
9

Doing a physics Lab and need to propagate uncertainty for experimental results. I need the uncertainty in order to add it to my

scatter plot for the error bars, therefore, I need both a positive and a negative error value. How is this done for my data? please show all work
373.67 +/- 15.444

210 +/- 12.82

239.33 +/- 19.98

443.67 +/- 17.99
Physics
1 answer:
alexandr1967 [171]3 years ago
8 0

Answer:

Explanation:

Not really sure what you're trying to do. You propagate uncertainties for indirect measurements, as in when you calculate a value from other values.

What you have here is a series of values of direct measurements it seems.

Anyway, for error bars will have a width of 2 times the uncertainty reported.

For example on the first one

373.67 +/- 15.444

You would have an error bar with a width of 2 * 15.444 = 30.888. This bar would be centered at 373.677. The lowest point of the error bar would be at 358.233 and the highest point at 389.121.

You also mentioned a scatter plot, but scatter plots are 2D at least. Are these measurements associated to something else like time? You need 2 coordinates for each point in a scatter plot.

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Answer:

The si unit to measure force are Pascels or Pa

Hope this helps

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I need someone to give me 2 answers,
yanalaym [24]
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When the flashlight is in the air and the refracted ray enters the water, how does the angle of refraction compare with the angl
tigry1 [53]

Answer:

The refracted angle will be less than the angle of incidence and the speed of light is slower in the new medium (which is water) and is closer to the normal.

Try remembering this by using FST SFA (Fast Sofa)

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4 0
3 years ago
Calculate the total energy of 2.0 kg object moving horizontally at 10 m/s 50 meters above the surface
mina [271]
We have:

Total Energy: KE + GPE
KE (Kinetic Energy) = \frac{1}{2} m*v^2
GPE (Gravitational Potential Energy) = m*g*h

Data:
m (mass) = 2.0 Kg
v (speed) = 10 m/s
h (height) = 50 m
Use: g (gravity) = 10 m/s²

Formula:

Total Energy: KE + GPE
TE =  \frac{1}{2} m*v^2 + m*g*h

Solving:
TE = \frac{1}{2} m*v^2 + m*g*h
TE = \frac{1}{2} *2.0*10^2 + 2.0*10*50
TE =  \frac{2.0*100}{2} + 1000
TE =  \frac{200}{2} + 1000
TE = 100 + 1000
\boxed{\boxed{TE = 1100\:Joule}}\end{array}}\qquad\quad\checkmark


5 0
3 years ago
Read 2 more answers
Work done(as a measure of energy)=force x distance. Use this equation to show that the SI base units of energy are kg m^2 s^-2
Arturiano [62]
Force [kgms^-2] = mass [kg] x acceleration [ms^-2]
Work = force x distance
Work = [kgms^-2] x [m]
Work = [kgm^2s^-2]
4 0
3 years ago
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