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ziro4ka [17]
3 years ago
9

Doing a physics Lab and need to propagate uncertainty for experimental results. I need the uncertainty in order to add it to my

scatter plot for the error bars, therefore, I need both a positive and a negative error value. How is this done for my data? please show all work
373.67 +/- 15.444

210 +/- 12.82

239.33 +/- 19.98

443.67 +/- 17.99
Physics
1 answer:
alexandr1967 [171]3 years ago
8 0

Answer:

Explanation:

Not really sure what you're trying to do. You propagate uncertainties for indirect measurements, as in when you calculate a value from other values.

What you have here is a series of values of direct measurements it seems.

Anyway, for error bars will have a width of 2 times the uncertainty reported.

For example on the first one

373.67 +/- 15.444

You would have an error bar with a width of 2 * 15.444 = 30.888. This bar would be centered at 373.677. The lowest point of the error bar would be at 358.233 and the highest point at 389.121.

You also mentioned a scatter plot, but scatter plots are 2D at least. Are these measurements associated to something else like time? You need 2 coordinates for each point in a scatter plot.

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A bowling ball with a mass of 7.0 kg, generates 56.0 kgᐧm/s units of momentum. What
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Answer:

8 m/s

Explanation:

p = mv \\ 56 = (7.0)(v) \\ v = 8.0 \: m {s}^{ - 1}

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Think about the difference between thermal energy and temperature. How might the melting icicles gain energy without changing te
ivann1987 [24]

No temperature change occurs from heat transfer if ice melts and becomes liquid water (i.e., during a phase change). For example, consider water dripping from icicles melting on a roof warmed by the Sun. Conversely, water freezes in an ice tray cooled by lower-temperature surroundings.

Hope this helped you

5 0
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An electric oven has a resistance of 201 ohms and a voltage of 220 V. How much current does it draw?
asambeis [7]

1.1 A. An electric oven with a resistance of 201Ω and a voltage of 220V drwa a current of 1.1 A.

The easiest way to solve this problem is using the Ohm's Law I = V/R.

An electric oven has R = 201Ω, and a drop of voltage V = 220v, solve using I = V/R:

I = 220V / 201Ω

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5 0
3 years ago
A radioactive material has a count rate of 400 per minute. It has a half life of 40 years. How long will it take to decay to a r
cestrela7 [59]

Answer:

160 years.

Explanation:

From the question given above, the following data were obtained:

Initial count rate (Cᵢ) = 400 count/min

Half-life (t½) = 40 years

Final count rate (Cբ) = 25 count/min

Time (t) =?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Initial count rate (Cᵢ) = 400 count/min

Final count rate (Cբ) = 25 count/min

Number of half-lives (n) =?

Cբ = 1/2ⁿ × Cᵢ

25 = 1/2ⁿ × 400

Cross multiply

25 × 2ⁿ = 400

Divide both side by 25

2ⁿ = 400/25

2ⁿ = 16

Express 16 in index form with 2 as the base

2ⁿ = 2⁴

n = 4

Thus, 4 half-lives has elapsed.

Finally, we shall determine the time taken for the radioactive material to decay to the rate of 25 counts per minute. This can be obtained as follow:

Half-life (t½) = 40 years

Number of half-lives (n) = 4

Time (t) =?

n = t / t½

4 = t / 40

Cross multiply

t = 4 × 40

t = 160 years.

Thus, it will take 160 years for the radioactive material to decay to the rate of 25 counts per minute.

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