The Image distance and Magnification of The Image will be 30 cm and 3.
<h3>What is focal length?</h3>
The focal length of the lens, which is often expressed in millimeters, is the distance between the lens and the image sensor when the subject is in focus.
Given data;
Focal length,f=?
Image distance,v=?
Object distance,u= 10 cm
Magnification,m= 2.85
The focal length is half of the radius;
f=R/2
f=30 Cm/2
f= 15 Cm
The mirror equation is found as;
The magnification of the lens is found as;
Hence, the image distance and magnification of The image will be 30 cm and 3.
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Height and depth..... for sure....
Answer:
1. Just because it is small doesn't mean it needs to be excluded. If that were the case I would've been out of my friend group a while ago
2. Look at it it's fricking beautiful (see attachment)
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opening announcement to announce the arrival of the gorgeouness.
A field is the description of a spatial region, the force exerted on objects by a field is a field force.
gravitational force field: surrounds every material object, although only objects planet-sized or larger exert significant gravity.
electric force field: surrounds and affect electrical charges
magnetic force field: surround magnets and materials with electricity flowing through them. magnetic fields affect susceptible materials such as iron or other magnets.
hope i helped a little
Answer:
19.5°
Explanation:
The energy of the mass must be conserved. The energy is given by:
1) 
where m is the mass, v is the velocity and h is the hight of the mass.
Let the height at the lowest point of the be h=0, the energy of the mass will be:
2) 
The energy when the mass comes to a stop will be:
3) 
Setting equations 2 and 3 equal and solving for height h will give:
4) 
The angle ∅ of the string with the vertical with the mass at the highest point will be given by:
5) 
where l is the lenght of the string.
Combining equations 4 and 5 and solving for ∅:
6) 
