What would be the approximate length of the parallelogram if the base were completely straight

Is 70 thousand written in standard form or word form ? Explain

Stolb23 [73]

<span>70 thousand is written in short word form, because its written as a combination of numbers and letters. Standard form would be to write the number easily using multiplication with 10. That woul be: 70000=7*10^4. It;s 10^4 because the decimal point has been 4 laces to the left to get the number to be 7. Word form can be obtain by writing the number using letters. Long word form is: seventy thousand. But because sevety is written with number (70), this is short word form of the number,</span>

5 0

3 years ago

Luke puts $35 in his savings account every month. Use a calculator to find how much money he will save in a year.

ipn [44]

420.00 that's how much he would have saved in a year

8 0

3 years ago

Graph the line whose y-intercept is -7 and whose x-intercept is 1

vesna_86 [32]

Answer:

$y=7x -7$

Step-by-step explanation:

We are given two points, the y - intercept and the x - intercept.

The y - intercept being: ( 0, -7 )

The x - intercept being: ( 1, 0 )

The equation of a line in slope - intercept form is:

y = mx + b, where m is the slope and b is the y - intercept.

We already have the y - intercept. So far we have:

y = mx - 7

What we're missing is the slope.

To find the slope, we can use this formula:

$\frac{y_{2}-y_{1} }{x_{2}-x_{1}}$ , where $x_{2}$ and $x_{1}$ are the x - coordinates of both points and $y_{2}$ and $x_{1}$ are the y - coordinates of both points.

$m=\frac{0-(-7)}{1-0} \\\\m=\frac{7}{1}\\m=7$

We now have the missing piece, the slope, so the equation now is:

$y=7x -7$

3 0

3 years ago

You draw 4 cards from a deck of 52 cards with replacement. What are the probabilities of drawing a black card on each of your fo

lawyer [7]

Solution:

As, in a pack of cards, there are 26 black cards and 26 red cards.

Probability of an event = $\frac{\text{total favorable outcome}}{\text{total possible outcome}}$

Probability of drawing a black card from a pack of 52 cards = $\frac{26}{52}=\frac{1}{2}$

As each card drawn is replaced,Each black card draw is an independent with another black card draw.

Probabilities of drawing a black card on each of four trial=

$\frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{2}=[\frac{1}{2}]^4$

4 0

3 years ago

Read 2 more answers

Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter

MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

$R_{3}$ = (x) = (e^z /4!)x^4

Since the aim is $R_{3}$ (x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 0

3 years ago