Can someone please answer my last question, ill post more like it for more points :)

Answer pls..... how????

Irina-Kira [14]

Answer:

E

C

B

D

A

Explanation:

The definition of words correspond well with the answers I provided and somewhat match with the dictionary definitions.

3 0

3 years ago

What is the name of the gas law relating pressure and volume at a constant temperature?

pochemuha

Answer:

Charles Law

Explanation:

Charles's law (also known as the law of volumes) is an experimental gas law that describes how gases tend to expand when heated. A modern statement of Charles's law is: This relationship of direct proportion can be written as: V∝T

5 0

3 years ago

Which of the following is ignored when determining the relative mass of atoms? (2 points)

QveST [7]

The atomic mass is determined by the number of protons and neutrons in a atoms for example oxygen has eight protons and neutrons which gives oxygen and atomic mass of 16

8 0

3 years ago

A solution is prepared by mixing 93.0 mL of 5.00 M HCl and 37.0 mL of 8.00 M HNO3. Water is then added until the final volume is

Charra [1.4K]

Answer:

$[H^{+}] = 0.761 \frac{mol}{L}$

$[OH^{-}]=1.33X10^{-14}\frac{mol}{L}$

$pH = 0.119$

Explanation:

HCl and HNO₃ both dissociate completely in water. A simple method is to determine the number of moles of proton from both these acids and dividing it by the total volume of solution.

$n_{H^{+} } from HCl = [HCl](\frac{mol}{L}). V_{HCl}(L) \\ n_{H^{+} } from HNO_{3} = [HNO_{3}](\frac{mol}{L}). V_{HNO_{3}}(L)$

Here, n is the number of moles and V is the volume. From the given data moles can be calculated as follows

$n_{H^{+} } from HCl = (5.00)(0.093)$

$n_{H^{+} } from HCl = 0.465 mol$

$n_{H^{+} } from HNO_{3} = (8.00)(0.037)$

$n_{H^{+} } from HNO_{3} = 0.296 mol$

$n_{H^{+}(total) } = 0.296 + 0.465$

$n_{H^{+}(total) } = 0.761 mol$

For molar concentration of hydrogen ions:

$[H^{+}] = \frac{n_{H^{+}}(mol)}{V(L)}$

$[H^{+}] = \frac{0.761}{1.00}$

$[H^{+}] = 0.761 \frac{mol}{L}$

From dissociation of water (Kw = 1.01 X 10⁻¹⁴ at 25°C) [OH⁻] can be determined as follows

$K_{w} = [H^{+} ][OH^{-} ]$

$[OH^{-}]=\frac{Kw}{[H^{+}] }$

$[OH^{-}]=\frac{1.01X10-^{-14}}{0.761 }$

$[OH^{-}]=1.33X10^{-14}\frac{mol}{L}$

The pH of the solution can be measured by the following formula:

$pH = -log[H^{+} ]$

$pH = -log(0.761)$

$pH = 0.119$

5 0

3 years ago

Step 2: measure the area of the top of the syringe

Elena L [17]

I am unsure if this is correct, but this might be the whole section:

The top of the syringe is a circle. You need to compute its area for use in later computations of pressure values. Start by using a ruler to measure the diameter. Estimate to the nearest 0.01 cm. Answer: 3.60 cm
Divide by two to find the radius. Maintain significant figures. Answer: 1.80 cm
Substitute the radius into the formula A = πr² to find the area of the top of the syringe. Maintain significant figures. Answer: 10.2 cm²

6 0

3 years ago