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2 years ago

50 J of work was done in order to move a chair 5 meters. what was the force applied to the chair

1 answer:

3 0

Using the Definition of Work, we have:

$T=F\DeltaS \\ 50=5F \\ \boxed {F=10N}$

If you notice any mistake in my english, please let me know, because i am not native.

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Which of the following codes is used to report the removal of 37 skin tags by electrosurgical destruction?

Tema [17]

Are there any answer choices??

7 0

3 years ago

Which of the following is true for a parallel circuit? The current is the same across all resistors in the circuit. The voltage

wel

A Parallel circuit has certain characteristics and basic rules: A parallel circuit has two or more paths for current to flow through. Voltage is the same across each component of the parallel circuit. The sum of the currents through each path is equal to the total current that flows from the source.

4 0

3 years ago

An object of irregular shape has a characteristic length of L = 0.5 m and is maintained at a uniform surface temperature of Ts =

goblinko [34]

Answer:

The value of the average convection coefficient is 20 W/Km².

Explanation:

Given that,

For first object,

Characteristic length = 0.5 m

Surface temperature = 400 K

Atmospheric temperature = 300 K

Velocity = 25 m/s

Air velocity = 5 m/s

Characteristic length of second object = 2.5 m

We have same shape and density of both objects so the reynold number will be same,

We need to calculate the value of the average convection coefficient

Using formula of reynold number for both objects

$R_{1}=R_{2}$

$\dfrac{u_{1}L_{1}}{\eta_{1}}=\dfrac{u_{2}L_{2}}{\eta_{2}}$

$\dfrac{h_{1}L_{1}}{k_{1}}=\dfrac{h_{2}L_{2}}{k_{2}}$

Here, $k_{1}=k_{2}$

$h_{2}=h_{1}\times\dfrac{L_{1}}{L_{2}}$

$h_{2}=\dfrac{q}{T_{2}-T_{1}}\times\dfrac{L_{1}}{L_{2}}$

Put the value into the formula

$h_{2}=\dfrac{10000}{400-300}\times\dfrac{0.5}{2.5}$

$h_{2}=20\ W/Km^2$

Hence, The value of the average convection coefficient is 20 W/Km².

7 0

3 years ago

b. Comparing and Contrasting Compare the change in atmospheric pressure with elevation to the change in water pressure

babunello [35]

Answer:

hfyn done hm jjhohhy u kk

3 0

3 years ago

Read 2 more answers

A proton, an electron, and a helium nucleus all move at speed v. Rank their de Broglie wavelengths from largest to smallest. Wri

MatroZZZ [7]

Answer:

The correct option is 'c':electron,proton,helium nucleus

Explanation:

The De-Broglie's wavelength of particle is given by

$\lambda =\frac{h}{mv}$

Thus we can see that wavelength is inversely related to mass of the particle since 'h' (Plank's constant) and velocity is same for all the particles

Thus we conclude that the the lightest particle will have the most wavelength

Electron being the lightest of the 3 particles will have the largest wavelength thus the correct option is 'c'. Since electron has the largest wavelength followed by proton and the least wavelength among the 3 is of helium.

6 0

3 years ago