Answer:
True
Explanation:
When a satellite is orbiting the earth, the centripetal force is balanced by the gravitational force as :

...........(1)
Where
M is the mass of the earth
m is the mass of the planet
From equation (1), the speed of the satellite depends only on the mass of the earth and the orbital radius.
So, If a payload of material is added until it doubles the satellite's mass, the earth's pull of gravity on this satellite will double but the satellite's orbit will not be affected. It is true.
Answer:
(for small oscillations)
Explanation:
The total energy of the pendulum is equal to:

For small oscillations, the equation can be re-arranged into the following form:

Where:
, measured in radians.
If the amplitude of pendulum oscillations is increase by a factor of 4, the angle of oscillation is
and the total energy of the pendulum is:

The factor of change is:


Answer:
7kgm/s
Explanation:
Using the law of conservation of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.
Let P1A and P1B be the initial momentum of the bodies A and B respectively
Let P2A and P2B be the final momentum of the bodies A and B respectively after collision.
Based on the law:
P1A+P2A = P1B + P2B
Given P1A = 5kgm/s
P2A = 0kgm/s(ball B at rest before collision)
P2A = -2.0kgm/s (negative because it moves in the negative x direction)
P2B = ?
Substituting the values in the equation gives;
5+0 = -2+P2B
5+2 = P2B
P2B = 7kgm/s
Answer:
230.26 N
Explanation:
Since the speed is constant, acceleration is zero hence the net force will be given by the product of mass, coefficient of friction and acceleration due to gravity
F=0.72*32.6*9.81=230.26 N
Answer:
f1/f2 =W1/W2 = 1/3
.0 f2 = 3f1
As ,
1/F= 1/f1 +1/f2
...1/40 = 1/f1 - 1/3f1
f1=> 80/3 cm
... f2 = 2f1 = 3 x 80/3 = 80 cm