50 J of work was done in order to move a chair 5 meters. what was the force applied to the chair
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Answer
mass of the block A = 20 Kg
mass of block B = 10 Kg
acceleration of Block A = ?
acceleration of Block B = ?
Assuming the magnitude of force = 124 N
Applying newton's second law
F = 2 T
T = F/2
now, Tension in the string =
T = 124/2 = 62 N
Weight of the block A
W = m₁ g
W = 20 x 9.8 = 196 N
Weight of the block B
W = m₂ g
W = 10 x 9.8
W = 98 N
Weight of blocks is greater than force applied by the pulley so, the blocks will not move.
Hence, acceleration of the block A and B = 0 m/s²
If the Force magnitude is increased to 294 N
T = F/2 = 294/2 = 147 N
Since this Force is less than Weight A acceleration of the block A = 0 m/s².
For Block B
Tension is more than Weight hence block will move
Net Force = 147 - 98 = 49 N
acceleration =
a = 4.9 m/s²