Answer:
1.23 m/s
Explanation:
p=mv
57.2 = 46.5v
v= 57.2/46.5
v= 1.23
If you want to verify your answer, just insert the value of v in the equation.
Answer:
(a). 14.4 lbf/in^2.
(b). 27.8 in, AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.
Explanation:
So, from the question above we are given the following parameters which are going to help us in solving this particular Question;
=> The "barometer accidentally contains 6.5 inches of water on top of the mercury column (so there is also water vapor instead of a vacuum at the top of the barometer)"
=> "On a day when the temperature is 70oF, the mercury column height is 28.35 inches (corrected for thermal expansion)."
With these knowledge, let us delve right into the solution;
(a). The barometric pressure = water vapor pressure + acceleration due to gravity (ft/s^2) × water density(slug/ft^3) × {ft/12 in}^3 × [ height of mercury column + specific gravity of mercury × height of water column].
The barometric pressure= 0.363 + {(62.146) ÷ (12^3) × 390.6425}. = 14.4 lbf/in^2.
(b). { (13.55 × length of mercury) + 6.5 } × (62.15÷ 12^3) = 14.4 - 0.603.
Length of mercury = 27.8 in.
AS THE TEMPERATURE INCREASES, THE LENGTH OF MERCURY DECREASES.
Kinetic energy per unit of mass is
Given, 
Therefore,
Now potential energy per unit mass is
Given, 
Therefore,
Thus, total mechanical energy of the river water per unit mass is
OR
Answer: cleft grafting, inlay grafting, four-flap grafting, and whip grafting.
Explanation:
I hope I helped , Have a great day or night . Xoxoxo.
Answer:
k = 22.05 N/m
Explanation:
The potential energy of the mass is converted into potential energy of the spring.
Given:
mass m = 0.27 kg
gravitational constant g = 9.8 m/s²
distance falling/ stretching of spring h = 0.24 m
Solving for k:
