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Elenna [48]
3 years ago
13

While an airplane is in flight, four forces act on it. Thrust is caused by the airplane's propellers pushing through the surroun

ding air, pulling the airplane forward. Drag is caused by the air smacking into the plane's surface, pushing it backward. Lift is caused by the air rushing over the wings, pushing it upward. And weight is caused by gravity pulling the plane downward. Which force acts on the plane at a distance?
Physics
2 answers:
IceJOKER [234]3 years ago
4 0
The answer would be weight
Iteru [2.4K]3 years ago
3 0

Among these 4 forces, the only force acting on the plane at a distance is weight.


In fact, weight is due to gravity, which is a non-contact force (it acts also from a distance). All the other forces, instead, are due to the contact between the plane (or parts of it) with the surrounding air: without the air, all the other 3 forces (thrust, lift, drag) would not be present, while weight would be always present.

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There are no rules that describe how positive energy behaves
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(Wellll ... in pop Psychology, perhaps, but not in any real science.)

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3 years ago
Once a scientist has made a hypothesis, what would they typically do next? (2 points)
ipn [44]

Answer:

b-testing

Explanation:

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Hope this helps.

4 0
3 years ago
A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
MAVERICK [17]

Answer:

t₂ = 3.89 s

Explanation:

given,

speed of car  = 23 m/s

speed of motorcycle = 23 m/s

after time of 4 s distance between them is equal to = 53 m

motorcycle accelerates at = 7 m/s

time taken to catch up with car = ?

let t₂ be the time in which motorcycle catches car.

distance traveled by car in t₂ s

d = 23 t₂ + 53

distance traveled by motorcycle

using equation of motion

s = ut + \dfrac{1}{2}at^2

s = 23 t_2 + \dfrac{1}{2}\times 7 \times t_2^2

now, equating both the distances

23t_2 + 53= 23 t_2 + \dfrac{1}{2}\times 7 \times t_2^2

t_2^2 = 15.143

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time taken by the motorcycle to catch the car is equal to 3.89 s

4 0
3 years ago
Does someone know how to do math with that equation
mestny [16]

Answer:

f = 5 cm

Explanation:

using the thin lens equation, given as follows:

\frac{1}{f} = \frac{1}{d_{o}}+\frac{1}{d_{i}}\\

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f = focal length = ?

do = the distance of object from lens = 20 cm

di = the distance of image from lens = 6.6667 cm

Therefore,

\frac{1}{f} = \frac{1}{20\ cm}+\frac{1}{6.6667\ cm}\\\\\frac{1}{f} =  0.199999\ cm^{-1}\\\\f = \frac{1}{0.199999\ cm^{-1}}\\\\

<u>f = 5 cm</u>

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An alien spacecraft flies directly over a football stadium at a speed of 0.50c. if the proper length of the field is 100 yards,
Ivahew [28]
Go on way and you will get your answer


6 0
3 years ago
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