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Elenna [48]
3 years ago
13

While an airplane is in flight, four forces act on it. Thrust is caused by the airplane's propellers pushing through the surroun

ding air, pulling the airplane forward. Drag is caused by the air smacking into the plane's surface, pushing it backward. Lift is caused by the air rushing over the wings, pushing it upward. And weight is caused by gravity pulling the plane downward. Which force acts on the plane at a distance?
Physics
2 answers:
IceJOKER [234]3 years ago
4 0
The answer would be weight
Iteru [2.4K]3 years ago
3 0

Among these 4 forces, the only force acting on the plane at a distance is weight.


In fact, weight is due to gravity, which is a non-contact force (it acts also from a distance). All the other forces, instead, are due to the contact between the plane (or parts of it) with the surrounding air: without the air, all the other 3 forces (thrust, lift, drag) would not be present, while weight would be always present.

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What is the disadvantage of the parallax method, especially for studying distant parts of the Galaxy?
Katena32 [7]

Answer and Explanation:

Parallax method is used for finding the distance of objects in space there are two types of parallax method that is stellar parallax and trigonometric parallax.The disadvantage of using parallax method is that it can can not reach so far in the Galaxy due to this reason parallax method is generally not used for measuring distance in galaxy.

6 0
4 years ago
You have a 16-kg suitcase. what work did you do when you have slowly lifted it 0.80 m upward?
Anna71 [15]
The formula is:
Work = Force · Displacement
F = m · g
F = 16 kg · 9.8 m/s²  = 156.8 N
and we know that:
d = 0.8 m
W = 156.8 N · 0.8 m = 125.44 J
Answer:
W = 125.44 J.
8 0
3 years ago
You attach a meter stick to an oak tree, such that the top of the meter stick is 1.87 meters above the ground. Later, an acorn f
Verdich [7]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. We will calculate the initial velocity of the object, and from it, we will calculate the final position. With the considerations made in the statement we will obtain the total height. Initial velocity of the acorn,

u = 0m/s

Also, it is given that the acorn takes 0.201s to pass the length of the meter stick.

s = ut+\frac{1}{2} at^2

Replacing,

1 = u(0.141)+ \frac{1}{2} (9.8)(0.141)^2

u =6.4013m/s

The height of the acorn above the meter stick can be calculated as,

v^2 = u^2 +2gh

h = \frac{v^2-u^2}{2g}

h = \frac{6.4013^2-0^2}{2(9.8)}

h = 2.0906m

Also the top of the meter stick is 1.87m above the ground hence the height of the acorn above the ground is

h = 2.0906+1.87

h = 3.9606m

4 0
4 years ago
Mark and Leo are doing a experiment to see if rocks float. Leo uses a sedimentary rock. Does it float? Why or why not?
mrs_skeptik [129]
No because the rock isn't hollow it is hard from the inside out so it sinks because of its mass
8 0
3 years ago
A 19 kg child is riding a 5.6 kg bike with a
icang [17]

Answer:

\mathrm{a.\:}123\:\mathrm{kg\cdot m/s},\\\mathrm{b.\:}95\:\mathrm{kg\cdot m/s},\\\mathrm{c.\:}28\:\mathrm{kg\cdot m/s}

Explanation:

The momentum of an object is given by:

p=mv, where m is the mass of the object and v is the velocity of the object.

a)

The mass of the child and bike together is 19+5.6=24.6 kilograms. Since they're moving at a velocity of 5.0 m/s, their momentum is:

p=24.6\cdot 5=\fbox{$123\:\mathrm{kg\cdot m/s}$}.

b)

The mass of the child is given as 19 kg. Since the child is on the bike moving at 5.0 m/s, it's implied the child is as well. Therefore, the momentum of the child is:

p=19\cdot 5=\fbox{$95\:\mathrm{kg\cdot m/s}$}.

c) The mass of the bike is given as 5.6 kg and it is moving at 5.0 m/s. Therefore, the momentum of the bike is:

<u />p=5.6\cdot 5=\fbox{$28\:\mathrm{kg\cdot m/s}$}<u />

4 0
3 years ago
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