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Elenna [48]
3 years ago
13

While an airplane is in flight, four forces act on it. Thrust is caused by the airplane's propellers pushing through the surroun

ding air, pulling the airplane forward. Drag is caused by the air smacking into the plane's surface, pushing it backward. Lift is caused by the air rushing over the wings, pushing it upward. And weight is caused by gravity pulling the plane downward. Which force acts on the plane at a distance?
Physics
2 answers:
IceJOKER [234]3 years ago
4 0
The answer would be weight
Iteru [2.4K]3 years ago
3 0

Among these 4 forces, the only force acting on the plane at a distance is weight.


In fact, weight is due to gravity, which is a non-contact force (it acts also from a distance). All the other forces, instead, are due to the contact between the plane (or parts of it) with the surrounding air: without the air, all the other 3 forces (thrust, lift, drag) would not be present, while weight would be always present.

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Calculate net force <br> 532N 215N
lorasvet [3.4K]

Answer:

FN is the forces acting on a body. When the body is at rest, the net force formula is given by, FNet = Fa + Fg.

Im in 7th and thats all I know so I hope it's enough

8 0
3 years ago
A 1200.0-kg car is traveling at 19m/s. The driver suddenly slams on the brakes and skids to a stop. The coefficient of kinetic f
Alja [10]
<h2>Answer</h2>

option D)

2.4 seconds

<h2>Explanation</h2>

Given in the question,

mass of car = 1200kg

speed of car = 19m/s

Force due to direction of travel

F = ma

  = 12000(a)

Force to due frictional force in reverse direction

-F = mg(friction coefficient)

   = -12000(9.81)(0.8)

<h2>-mg(friction coefficient) = ma  </h2>

(cancelling mass from both side of equation)

g(0.8) = a

(9.81)(0.8) = a

a = 7.848 m/s²

<h2>Use Newton Law of motion</h2><h3>vf - vo = a • t</h3>

where vf = final velocity

          vo = initial velocity

          a = acceleration

           t = time

0 - 19 = 7.8(t)

t = 19/7.8

  = 2.436 s

  ≈ 2.4s

5 0
3 years ago
If 2.0×10^−4 C of charge passes a point in 2.0×10^−6 s , what is the rate of current flow?1.0×10^−10 A1.0×10^2 A4.0×10^−1 A4.0×1
Ipatiy [6.2K]

This problem is about the rate of the current. It's important to know that refers to the quotient between the electric charge and the time, that's the current rate.

I=\frac{Q}{t}

Where Q = 2.0×10^−4 C and t = 2.0×10^−6 s. Let's use these values to find I.

\begin{gathered} I=\frac{2.0\times10^{-4}C}{2.0\times10^{-6}\sec } \\ I=1.0\times10^{-4-(-6)}A \\ I=1.0\times10^{-4+6}A \\ I=1.0\times10^2A \end{gathered}

<em>As you can observe above, the division of the powers was solved by just subtracting their exponents.</em>

<em />

<h2>Therefore, the rate of the current flow is 1.0×10^2 A.</h2>
3 0
1 year ago
An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the righ
Verdich [7]

The correct answer is: +5

Explanation:

An object is placed at 0; it means:

Initial position of the object = 0.

Now it moves to 3 units to right, so keeping the standard cartesian coordinate system in mind (in right right x-axis is positive and left x-axis is right), the new position of the object will be +3.

Object now moves 4 units to the left, it means +3 - 4 = -1; object is at the position -1.

Object then moves 6 units to the right, therefore,

Final position of the object = -1 + 6 = +5.

Displacement = Final position - Initial position

Displacement = +5 - 0 = +5

6 0
3 years ago
Read 2 more answers
Pouvez vous m'aider dans ce devoir sil vous plait.​
ahrayia [7]

in english please

i don't understand actually

8 0
3 years ago
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