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Elenna [48]
4 years ago
13

While an airplane is in flight, four forces act on it. Thrust is caused by the airplane's propellers pushing through the surroun

ding air, pulling the airplane forward. Drag is caused by the air smacking into the plane's surface, pushing it backward. Lift is caused by the air rushing over the wings, pushing it upward. And weight is caused by gravity pulling the plane downward. Which force acts on the plane at a distance?
Physics
2 answers:
IceJOKER [234]4 years ago
4 0
The answer would be weight
Iteru [2.4K]4 years ago
3 0

Among these 4 forces, the only force acting on the plane at a distance is weight.


In fact, weight is due to gravity, which is a non-contact force (it acts also from a distance). All the other forces, instead, are due to the contact between the plane (or parts of it) with the surrounding air: without the air, all the other 3 forces (thrust, lift, drag) would not be present, while weight would be always present.

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Draw the vector c⃗ =1.5a⃗ −3b⃗
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<span>The magnitude of a is 1.5
The magnitude of b is -3
The magnitude of the vector is
</span>√(1.5² + (-3)²) = 3.35
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1) If you release a rubber band that had 10 units of elastic energy, 12 units of movement energy cannot be produced. Why not?
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Answer:

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Explanation:

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3 years ago
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Describe the three particles that make up an atom (name, charge, and location in the atom).
kow [346]

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3 years ago
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A horizontal force of 40N is needed to pull a 60kg box across the horizontal floor at which coefficient of friction between floo
Mazyrski [523]

Answer:

Coefficient of friction is 0.068.

Work done is 320~J.

Explanation:

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Mass of the box (m): 60 kg

Force needed (F): 40 N

The formula to calculate the coefficient of friction between the floor and the box is given by

F=\mu mg...................(1)

Here, \mu is the coefficient of friction and g is the acceleration due to gravity.

Substitute 40 N for F, 60 kg for m and 9.80 m/s² for g into equation (1) and solve to calculate the value of the coefficient of friction.

40 N=\mu\times60 kg\times9.80 m/s^{2} \\~~~~~\mu=\frac{40 N}{60 kg\times9.80 m/s^{2}}\\~~~~~~~=0.068

The formula to calculate the work done in overcoming the friction is given by

W=Fd..........................(2)

Here, W is the work done and d is the distance travelled.

Substitute  40 N for F and 8 m for d into equation (2) to calculate the work done.

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3 years ago
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