Because 2 carbon attach to one's of each of the others
        
             
        
        
        
Impulse in physics is the integral of force, F, with respect with time, t. This value is a vector quantity since force is a vector quantity as well. It can be calculated from the product of force and time. We do as follows:
Impulse = Ft
               = m(a)(t)
               = m(v/t)t
               = 0.046 (42/0.0005) (0.0005)
               = 1.932 N-s
        
             
        
        
        
To solve this problem it is necessary to apply the concepts given in the kinematic equations of movement description.
From the perspective of angular movement, we find the relationship with the tangential movement of velocity through

Where,
 Angular velocity
Angular velocity
v = Lineal Velocity
R = Radius 
At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is

Where
 Angular acceleration
Angular acceleration
 Angular velocity
 Angular velocity
t = Time 
Our values are




Replacing at the previous equation we have that the angular velocity is



Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s
At the same time the angular acceleration would be



Therefore the angular acceleration of a point on the outer edge of the tires is 
 
        
             
        
        
        
Using 
F= mv²/r 
4 = 0.5×v² / 2 
8 /0.5 = v² 
v²=16 
v= √16 
v= 4 ms-¹
        
             
        
        
        
Answer:

Explanation:
Given that,
The initial speed of a car, u = 0
Time, t = 18 s
Distance, d = 390 m
We need to find the acceleration of the car. Let it is a. Using the second equation of motion to find it.

or

So, the acceleration of the car is  .
.