Answer:
-2024 kJ
Explanation:
The combustion of propane is
C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(g)
And, ΔG° = ΔH° - TΔS°
Where T is the temperature in K.
ΔH° = ∑n*H°f, reactants - ∑n*H°f, products
Where n is the number of moles in the stoichiometry reaction. H°f, O₂(g) = 0 because it's a substance formed by only one element.
ΔH° = [4*(-226) +3*(-398)] - [-100] = -1998 kJ
ΔS° = ∑n*S°, reactants - ∑n*S°, products
ΔS° = [4*(184) + 3*214] - [5*204 + 271] = 87 J/K = 0.087 kJ/K
So
ΔG° = -1998 - 298*0.087
ΔG° = -2024 kJ
Explanation:
More quickly a reactant will disappear, the more quickly it will result in the formation of products. This means that consumption or disappearance of reactants determines the rate of a reaction because only then products will be formed.
Thus, we can conclude that measuring how quickly a reactant disappears is one way to measure the rate of the reaction.
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Lysosomes are simlar to vacuoles by them working together basically. they both are enclosed organelle compartments within cell. vacuoles store the food waste, bacteria, etc. while the lysosomes breaks them down
MgF2 + H2
Fluorine now has a subscript of 2 due to the fact that Magnesium has a charge of two; swap and drop rules applied means that it switches over to Fluorine.
Hydrogen has a charge of two as it's one of the diatomic elements, meaning it has a charge of two when alone. The other diatomic elements are Fluorine, Oxygen, Nitrogen, and the Halogens.
Hope this helps!
