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3 years ago

What is the complete ionic equation for this reaction?

Chemistry

1 answer:

geniusboy [140]3 years ago

5 0

Answer:

The answer is "Option D".

Explanation:

The entire ionic equation for all the substances, which are ionic compounds but are available in an aquatic is represented in the form with ions in the full ionic equation.

In the Net ionic equation, it doesn't have the particulate matter throughout the net ionic equations throughout the equations.

In the Spectator ions, it doesn't participate in interactions mostly on reaction and the material hand. From both sides, the very same ions are present.

The evenly balanced chemical formula is,

$2KOH (aq)+ H_2SO_4(aq) \longrightarrow 2H_2O(l) + K_2SO_4$

It is the separate organic compound that full ion formula will match the choice D.

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3. A reaction produces 14.2 grams of a product. The theoretical yield of that product

nlexa [21]

A reaction that produces 14.2 grams of a product and the theoretical yield of that product is 17.1 grams is true for the following statements :

The percent yield of the product is 83.0%

The actual yield of the product is 14.2 grams.

<h3>Percentage Yield:</h3>

Percent yield is the percent ratio of actual yield to the theoretical yield.

Mathematically,

percent yield = actual yield / theoretical yield x 100%

actual yield = 14.2 grams

theoretical yield = 17.1 grams

percentage yield = 14.2 / 17.1 × 100%

percentage yield = 83.0409356725 %

percentage yield = 83.0 %

Therefore,

The percent yield of the product is 83.0%

The actual yield of the product is 14.2 grams.

learn more on percentage yield here; brainly.com/question/4180677

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3 years ago

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

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3 years ago

The quinine in tonic water shines a strange blue-white colour when lit with UV light. Explain what is happening here.

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Answer:

Here's what I get.

Explanation:

Quinine contains phosphors, substances that glow when they are hit with certain wavelengths of light.

The phosphors in quinine absorb UV light, which is invisible to our eyes.

Electrons in the phosphors absorb the UV energy and are excited to higher energy levels.

When the electrons drop back to lower energy levels, they emit some of this energy as a glowing blue visible light.

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3 years ago

How many significant figures are in the following number? 0.000485

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Answer:

4 or 3

Explanation:

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