1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natta225 [31]
3 years ago
6

A certain substance X has a normal freezing point of -10.1 degree C and a molal freezing point depression constant K_f = 5.32 de

gree C middot kg middot mol^-1. Calculate the freezing point of a solution made of 29.82 g of urea ((NH_2)_CO) dissolved in 500. g of X. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
kirill115 [55]3 years ago
7 0

Answer: -15.4^00C

Explanation:

T^0_f-T_f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_f = boiling point of solution = ?

T^o_f = boiling point of solvent (X) = -10.1^oC

k_f = freezing point constant  = 5.32^oC/kgmol

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte like urea)

= mass of solute (urea) = 29.82 g

= mass of solvent (X) = 500.0 g

M_2 = molar mass of solute (urea) = 60 g/mol

Now put all the given values in the above formula, we get:

(-10.1-(T_f))^oC=1\times (5.32^oC/m)\times \frac{(29.82g)\times 1000}{60\times (500.0g)}

T_f=-15.4^0C

Therefore, the freezing point of  solution is -15.4^0C

You might be interested in
Why must chemical equations be balanced?
Elina [12.6K]

Answer:

to validate the law of conservation of mass as total no. of reactants must be equal to the total no. of products

5 0
3 years ago
ILL GIVE U 100 POINTS!!!!
Alexxx [7]

✿<em>I'll </em><em>take</em><em> </em><em>that</em><em> </em><em>5</em><em>0</em><em> </em><em>pts</em><em> </em>✿

<em>✨</em><em>Refer</em><em> </em><em>these</em><em> </em><em>attachments</em><em>,</em><em> </em><em>for</em><em> </em><em>your</em><em> </em><em>answer</em><em> </em><em>✨</em>

<em>hope it helps</em> ❤~

✨luv, Snowflake✨

6 0
2 years ago
Read 2 more answers
List the number of protons, neutrons, and electrons in....( there is a pic)
notsponge [240]
There are 6 protons, 7 neutrons, and 6 electrons since the atomic mass is rounded to 13.
3 0
3 years ago
How many moles are in 5.4x1024 molecules of C4H2F7I, heptafluoro-1-iodobutane? Group of answer choices
jasenka [17]

Given :

Number of molecules of C_4H_2F_7I.

To Find :

How many moles are in given number of molecules.

Solution :

We know, in 1 moles of any element/compound contains 6.022\times 10^{23} at atoms/molecules.

So, number of moles in 5.4\times 10^{24} molecules are :

n = \dfrac{5.4\times 10^{24}}{6.022\times 10^{23}}\\\\n = 8.97 \ moles

Therefore, number of moles are 8.97 .

4 0
2 years ago
people can increase water conservation by eating more food drinking more water taking longer showers reducing water pollution
hram777 [196]
Reduce water pollution
8 0
3 years ago
Read 2 more answers
Other questions:
  • (True or False) It would be most appropriate to use the noble gas core [He] when writing the shorthand electron configuration fo
    12·2 answers
  • What’s the answer? And if you find the answer in a pdf, comment the link.
    13·1 answer
  • How many electrons can occupy the s orbitals at each energy level?
    9·1 answer
  • Solve the question that follows using the equation for the conversion of Celsius to Fahrenheit. F=95(C)+32 On February 9, 1934,
    8·1 answer
  • What is the energy of a photon of green light whose frequency is 6.85 X 1014/seC?
    8·1 answer
  • Which of the following substances are likely to be soluble in water?
    10·1 answer
  • An energy pyramid shows the amount of _________ available at each feeding level in an ecosystem
    7·2 answers
  • Subtract to find the temperature changes<br><br> for the water and the metal.
    13·1 answer
  • What happens in the body when we break down carbohydrates? Explain the whole course of events.
    11·1 answer
  • How much solar radiation is reflected back by clouds?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!