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2 years ago

Name an insoluble cobalt salt

1 answer:

amm18122 years ago

6 0

Cobalt sulphate is the usual source of water-soluble cobalt since it is the most economical salt and shows less tendency to deliquesce or dehydrate

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Write the appropriate symbol for each of the following isotopes: (a) Z 11, A 23; (b) Z= 28, A= 64; (c) Z= 50, A =115; (d) Z= 20,

prohojiy [21]

Explanation:

Z = atomic mass of the element and , A = atomic mass of the element .

a) Z = 11, A = 23

Element = Sodium

symbol: ²³₁₁Na .

b) Z = 28, A = 64

Element = Nickel

symbol: ⁶⁴₂₈Ni .

c) Z = 50, A = 115

Element = tin

symbol: ¹¹⁵₅₀Sn .

d) Z = 20, A = 42

Element = Calcium

symbol: ⁴²₂₀Ca .

6 0

3 years ago

Read 2 more answers

24-Complete the following sentence:

docker41 [41]

Answer:

B. Solvent

Explanation:

In osmosis, water always moves from low solute concentration to high solute concentration. SOLUTE NEVER MOVES AS IT CANNOT PASS THE SELECTIVELY PERMEABLE MEMBRANE. alot of caps but need to stress this concept cuz otherwise this concept gets very confusing

8 0

3 years ago

Calculate the density of chloroform

Rina8888 [55]

Answer: The density of chloroform is 1.47 g/mL

Explanation : Given,

Volume = 40.5 mL

Mass of cylinder = 85.16 g

Mass of cylinder and liquid = 145.10 g

First we have to calculate the mass of liquid (chloroform).

Mass of liquid = Mass of cylinder and liquid - Mass of cylinder

Mass of liquid = 145.10 g - 85.6 g

Mass of liquid = 59.5 g

Now we have to calculate the density of liquid (chloroform).

Formula used:

$Density=\frac{Mass}{Volume}$

Now putting g all the given values in this formula, we get:

$Density=\frac{59.5g}{40.5mL}$

$Density=1.47g/mL$

Therefore, the density of chloroform is 1.47 g/mL

5 0

2 years ago

1. Write the balanced equation for the breakdown of hydrogen peroxide. The equation has been written, you just have to balance.

o-na [289]

The balanced equation is attached in the image below. The coefficients are 2, 2, blank.

7 0

3 years ago

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When 551. mg of a certain molecular compound X are dissolved in 100 g of benzonitrile (CH,CN), the freezing point of the solutio

arsen [322]

Answer:

1.12g/mol

Explanation:

The freezing point depression of a solvent for the addition of a solute follows the equation:

ΔT = Kf*m*i

Where ΔT is change in temperature (Benzonitrile freezing point: -12.82°C; Freezing point solution: 13.4°C)

ΔT = 13.4°C - (-12.82) = 26.22°C

m is molality of the solution

Kf is freezing point depression constant of benzonitrile (5.35°Ckgmol⁻¹)

And i is Van't Hoff factor (1 for all solutes in benzonitrile)

Replacing:

26.22°C = 5.35°Ckgmol⁻¹*m*1

4.90mol/kg = molality of the compound X

As the mass of the solvent is 100g = 0.100kg:

4.9mol/kg * 0.100kg = 0.490moles

There are 0.490 moles of X in 551mg = 0.551g, the molar mass (Ratio of grams and moles) is:

0.551g / 0.490mol

= 1.12g/mol

This result has no sense but is the result by using the freezing point of the solution = 13.4°C. Has more sense a value of -13.4°C.

5 0

2 years ago

Name an insoluble cobalt salt​

Name an insoluble cobalt salt